Lol
trouble varies directly as distance
lets say t=trouble and d=distance
t=kd
k is constant
given
when t=20, and d=400
find k
20=400k
divide by 400 both sides
1/20=k
t=(1/20)d
given, d=60
find t
t=(1/20)60
t=60/20
t=3
3 troubles
Answer:
16 apples, 20 pears
Step-by-step explanation:
36+4=40
So 40/2= 20 or an even amount of both apples and pears
20-4= 16 ~Original amount of apples
36-16=20 ~Amount of pears
Marlee will have 21.05 inches of wire left, here is why;
115-25.75=89.25
89.25+30=119.25
119.25-38=81.25
81.25-60.2=21.05
She has 21.05 inches of wire left.
First, let x be the number of hours it will take for Hector to finish the same job alone. This means that every hour, Hector can do 1/x of the job. The amount of work done by Shawn and Hector in 6 hours should be equal to 1 complete work. This can be expressed as,
(1/9 + 1/x)(6) = 1
The value of x is 18. Thus, Hector can to 1/18 of the job in one hour.
Okay so you're trying to find the unit rate of 720yds/4min. If you divide 720 by 4 you will have the unit rate as 180yds/1 min or 60 sec then if you divide 180 and 60 by 4 again you will get the answer of 45yds/15sec.
