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Ilia_Sergeevich [38]
1 year ago
6

A submarine dives 55 meters below its original location and then rises.

Mathematics
1 answer:
maksim [4K]1 year ago
8 0

Answer:

original position was 134

distance between dive and rise was 127

Step-by-step explanation:

"dives 55 meters" 189-55=134

189-62=127

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GIVING BRAINLIEST
Umnica [9.8K]

Answer:

140

Step-by-step explanation:

180 - 40 = 140

7 0
2 years ago
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Really need help! Brainliest to correct!
zlopas [31]

Answer:

<u>Given</u>:

  • R(x) = 59x - 0.3x²
  • C(x) = 3x + 14

<u>Find the following</u>:

  • P(x) = R(x) - C(x) = 59x - 0.3x² - 3x - 14 = -0.3x² + 56x - 14
  • R(80) = 59(80) - 0.3(80²) = 2800
  • C(80) = 3(80) + 14 = 254
  • P(80) = 2800 - 254 = 2546
7 0
2 years ago
Please help me !!!!!!!!
astraxan [27]
It's C the missing side is 9 units long so since cosine is adjacent divided by hypotenuse it would be 9/41
5 0
2 years ago
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Can someone help me with these and show the work also?
Snezhnost [94]

QUESTION:

Simplify each expression

ANSWER:

1.) \green{{- 8n}}

2.) \green{{- 2b - 60}}

3.) \green{{- 10x - 14}}

4.) for number 4 study my step-by-step explanation so you can answer that

STEP-BY-STEP EXPLANATION:

1.) First, If the term doesn't have a coefficients, it is considered that the coefficients is 1

WHY?

Learn why:

Why is it considered that the coefficient is 1?

Remember that any term multiplied by \blue{{1}} remains the same :

\blue{{1}} {× x = x}

Step 1:

The equality can be read in the other way as a well, so any term can be written as a product of \blue{{1}} and itself:

{x = } \blue{{1}} {× x}

Step 2:

Usually, we don't need to write multiplacation sign between the coefficient and variable, so the simple form is:

{x = 1x}

This is why we can write the term without the coefficient as a term with coefficient {1}

Now let's go back to solving as what i said if a term doesn't have a coefficient, it is considered that the coefficient is 1

{n - 9n}

\red{{1}} {n -9n}

Second, Collect like terms by subtracting their coefficients

\red{{1n - 9n}}

\red{{( 1 - 9)n}}

Third, Calculate the difference

how?

Keep the sign of the number with the larger absolute value and subtract the smaller absolute value from larger

\red{{1 - 9}}

\red{{- (9 - 1)}}

Subtract the numbers

- (\red{{9 - 1}})n

- \red{{8}}n

\green{\boxed{- 8n}}

2.) First, Distribute - 6 through the parentheses

how?

Multiply each term in the parentheses by - 6

\red{{- 6(b + 10)}}

\red{{- 6b - 6 × 10}}

Multiply the numbers

- {6b} - \red{{6 × 10}}

- {6b} - \red{{60}}

Second, Collect like term

how?

Collect like terms by calculating the sum or difference of their coefficient

\red{{- 6b + 4b}}

\red{{(- 6 + 4)b}}

Calculate the sum

\red{{(- 6 + 4)}}b

\red{{-2}}b

\green{\boxed{- 2b - 60}}

3.) First, Distribute 2 through parentheses

how?

Multiply each term in the parentheses by 2

\red{{2(x - 5)}}

\red{{2x - 2 × 5}}

Multiply the numbers

{2x -} \red{{2 × 5}}

{2x -} \red{{10}}

Second, Distribute - 4 through the parentheses

how?

Multiply each term in the parentheses by - 4

\red{{- 4(3x + 1)}}

\red{{- 4 × 3x - 4}}

Calculate the product

- \red{{4 × 3}}x - 4

- \red{{12}}x - 4

Third, Collect like terms

how?

Collect like terms by subtracting their coefficient

\red{{2x - 12x}}

\red{{(2 - 12)x}}

Calculate the difference

\red{{(2 - 12)}}x

\red{{- 10}}x

Fourth, Calculate the difference

how?

Factor out the negative sign from the expression

\red{{- 10 - 4}}

\red{{- (10 + 4)}}

Add the numbers

- (\red{{10 + 4}})

- \red{{14}}

\green{\boxed{- 10x - 14}}

That's all I know sorry but I hope it helps :)

6 0
2 years ago
If the diameter of circle C is 3 times greater than the diameter of circle D, the area of circle C is how many times the area of
amid [387]
The radius of circle C is also 3 times greater than the radius of circle D.
The area of circle C:
A C = (3r)² π = 9 r² π
The area of circle D:
A D = r² π
9 r² π : r ² π = 9
Answer: It is 9 times the area of circle D.
7 0
3 years ago
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