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3 years ago

The tree in Nicole's backyard is 7.9 m high. How high is it in centimeters?

Mathematics

2 answers:

Mrrafil [7]3 years ago

8 0

Answer:

790cm

Step-by-step explanation:

1m=100cm

MaRussiya [10]3 years ago

5 0

<u>Answer: </u>

The tree in Nicole’s backyard is 7.9m. It’s height in centimeter is 790

<u>Solution: </u>

Given that the tree in nicole’s backyard is 7.9m high. We have to convert 7.9m to centimeter

To convert metre(m) to cemtimeter(cm) we use the given formula

We know,

1m =100 cm

Therefore to convert any number in metre (m) to centimeter (cm) we multiply the given number by 100.

Here we have to convert 7.9 m to cm. Therefore multiplying 7.9 with 100 we get,

$7.9 \times 100 = 790 cm.$

Thus the height of the tree in nicole’s backyard in cm is 790 cm.

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maria [59]

Answer:

cos(a + b) = $\frac{1}{12}(1-2\sqrt{30})$

Step-by-step explanation:

cos(a + b) = cos(a).cos(b) - sin(a).sin(b) [Identity]

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Since, terminal side of angle 'a' lies in quadrant 3, sine of angle 'a' will be negative.

sin(a) = $-\sqrt{1-(-\frac{1}{3})^2}$ [Since, sin(a) = $\sqrt{(1-\text{cos}^2a)}$ ]

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Similarly, terminal side of angle 'b' lies in quadrant 2, sine of angle 'b' will be negative.

sin(b) = $-\sqrt{1-(-\frac{1}{4})^2}$

= $-\sqrt{\frac{15}{16}}$

= $-\frac{\sqrt{15}}{4}$

By substituting these values in the identity,

cos(a + b) = $(-\frac{1}{3})(-\frac{1}{4})-(-\frac{2\sqrt{2}}{3})(-\frac{\sqrt{15}}{4})$

= $\frac{1}{12}-\frac{\sqrt{120}}{12}$

= $\frac{1}{12}(1-\sqrt{120})$

= $\frac{1}{12}(1-2\sqrt{30})$

Therefore, cos(a + b) = $\frac{1}{12}(1-2\sqrt{30})$

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2 years ago

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Dmitry_Shevchenko [17]

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<img src="https://tex.z-dn.net/?f=%28-5x%5E3%29%5E3%2F%2810x%5E5%29%5E2" id="TexFormula1" title="(-5x^3)^3/(10x^5)^2" alt="(-5x^

marta [7]

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