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12345 [234]
3 years ago
13

The tree in Nicole's backyard is 7.9 m high. How high is it in centimeters?

Mathematics
2 answers:
Mrrafil [7]3 years ago
8 0

Answer:

790cm

Step-by-step explanation:

1m=100cm

MaRussiya [10]3 years ago
5 0

<u>Answer: </u>

The tree in Nicole’s backyard is 7.9m. It’s height in centimeter is 790

<u>Solution: </u>

Given that the tree in nicole’s backyard is 7.9m high. We have to convert 7.9m to centimeter

To convert metre(m) to cemtimeter(cm) we use the given formula

We know,

1m =100 cm

Therefore to convert any number in metre (m) to centimeter (cm) we multiply the given number by 100.

Here we have to convert 7.9 m to cm. Therefore multiplying 7.9 with 100 we get,

7.9 \times 100 = 790 cm.

Thus the height of the tree in nicole’s backyard in cm is 790 cm.

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a slitter assembly contains 48 blades five blades are selected at random and evaluated each day for sharpness if any dull blade
12345 [234]

Answer:

P(at least 1 dull blade)=0.7068

Step-by-step explanation:

I hope this helps.

This is what it's called dependent event probability, with the added condition that at least 1 out of 5 blades picked is dull, because from your selection of 5, you only need one defective to decide on replacing all.

So if you look at this from another perspective, you have only one event that makes it so you don't change the blades: that 5 out 5 blades picked are sharp. You also know that the probability of changing the blades plus the probability of not changing them is equal to 100%, because that involves all the events possible.

P(at least 1 dull blade out of 5)+Probability(no dull blades out of 5)=1

P(at least 1 dull blade)=1-P(no dull blades)

But the event of picking one blade is dependent of the previous picking, meaning there is no chance of picking the same blade twice.

So you have 38/48 on getting a sharp one on your first pick, then 37/47 (since you remove 1 sharp from the possibilities, and 1 from the whole lot), and so on.

Also since are consecutive events, you need to multiply the events.

The probability that the assembly is replaced the first day is:

P(at least 1 dull blade)=1-P(no dull blades)

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P(at least 1 dull blade)=1-0.2931

P(at least 1 dull blade)=0.7068

6 0
3 years ago
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