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abruzzese [7]
3 years ago
12

Which equation(s) represents a line that contains the point (-8,3) and is perpendicular to =4x - 7 ?

Mathematics
1 answer:
Alinara [238K]3 years ago
8 0
Y=-1/4x+1 , is the answer

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10

Step-by-step explanation:

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Consider the given function and the given interval.
docker41 [41]

Answer:

  (a)  fave = 8

  (b)  c = 64/9

  (c)   c ≈ 7.111

Step-by-step explanation:

(a) The average value of the function is its integral over the interval, divided by the width of the interval.

  f_{ave}=\displaystyle\frac{1}{16-0}\int_0^{16} {3x^{\frac{1}{2}}} \, dx=\left.\frac{x^{3/2}}{8}\right|_0^{16}=8

__

(b) We want ...

  f(c) = 8

  3√c = 8 . . . . . use f(c)

  √c = 8/3 . . . . . divide by 3

  c = (8/3)² . . . . square

  c = 64/9

__

(c) c ≈ 7.111

7 0
3 years ago
Guys please help me out ASAP, Due today. I
Mice21 [21]

Answer:

T_7 = 11

T_n = 2n- 3

Step-by-step explanation:

Given

S_n = n^2 -2n

T_n = S_n - S_{n-1}

Solving (a): T7

Substitute 7 for n in T_n = S_n - S_{n-1}

T_7 = S_7 - S_{7-1}

T_7 = S_7 - S_6

Calculate S7 and S6

S_n = n^2 -2n

S_7 = 7^2 - 2 * 7 = 35

S_6 = 6^2 - 2 * 6 = 24

So:

T_7 = 35 -24

T_7 = 11

Solving (b): Tn

T_n = S_n - S_{n-1}

Where S_n = n^2 -2n

CalculateS_{n-1}

We have:

S_{n-1} =(n-1)^2 - 2(n-1)

Open brackets

S_{n-1} = n^2 -2n + 1 -2n +2

S_{n-1} = n^2 -2n-2n + 1  +2

S_{n-1} = n^2 -4n + 3

So:

T_n = S_n - S_{n-1}

T_n = n^2 - 2n - (n^2 -4n + 3)

T_n = n^2 - 2n - n^2 +4n - 3

Collect Like Terms

T_n = n^2 - n^2- 2n  +4n - 3

T_n = 2n- 3

5 0
3 years ago
I don’t understand Please help!
AlekseyPX

Answer:

The answer is water.........

5 0
3 years ago
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