Answer:
C
Step-by-step explanation:
Answer:
Third option
Step-by-step explanation:
We can't factor this so we need to use the quadratic formula which states that when ax² + bx + c = 0, x = (-b ± √(b² - 4ac)) / 2a. However, we notice that b (which is 6) is even, so we can use the special quadratic formula which states that when ax² + bx + c = 0 and b is even, x = (-b' ± √(b'² - ac)) / a where b' = b / 2. In this case, a = 1, b' = 3 and c = 7 so:
x = (-3 ± √(3² - 1 * 7)) / 1 = -3 ± √2
Answer:
its.....D
Step-by-step explanation:
Answer:
5! and 6p3
Step-by-step explanation:
5! = 5*4*3*2*1 = 120
6p3= n!/(n-r)!
where n = 6
and r = 3
6p3 = 6!/(6-3)!
= 6*5*4*3*2*1/3*2*1
= 120