Question

Use the quadratic formula to find both solutions to the quadratic equation

Answer 1

Answer:

$-\frac{5}{2} ;1.$

Step-by-step explanation:

2x² + 3x-5=0;

$\left[\begin{array}{ccc}x=\frac{-3-\sqrt{3^2+4*5*2}}{2*2} \\x=\frac{-3+\sqrt{3^2+4*5*2} }{2*2} \end{array} \ = > \ \left[\begin{array}{ccc}x=-\frac{5}{2} \\x=1\end{array}$