Answer:

Step-by-step explanation:
we know that
The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces
so
![SA=b^{2}+4[\frac{1}{2}bh]](https://tex.z-dn.net/?f=SA%3Db%5E%7B2%7D%2B4%5B%5Cfrac%7B1%7D%7B2%7Dbh%5D)
where
b is the length side of the square base
h is the height of the triangular face
Remember that
Each lateral triangular face is a triangle 45°-90°-45°
so

we have

so

substitute in the formula
![SA=6^{2}+4[\frac{1}{2}(6)(3)]=72\ ft^{2}](https://tex.z-dn.net/?f=SA%3D6%5E%7B2%7D%2B4%5B%5Cfrac%7B1%7D%7B2%7D%286%29%283%29%5D%3D72%5C%20ft%5E%7B2%7D)
Answer:
reflection over the x-axis and a vertical compression by a factor of 8
Step-by-step explanation:
The parent function is given as

The transformed graph has equation:

The factor of 8, indicates a vertical stretch.
The negative sign indicates a reflection in the x-axis.
Therefore the transformation is a reflection over the x-axis and a vertical compression by a factor of 8.
<h3>
Answer: Choice 2) sin(B) = cos(90-B)</h3>
Explanation:
The rule is that
sin(A) = cos(B)
if and only if A+B = 90.
Solving for A gets A = 90-B
So we end up with
sin(90-B) = cos(B)
which is the same as
cos(B) = sin(90-B)
Answer:
Area of the shaded region = 6.88 cm²
Step-by-step explanation:
Area of the shaded region = Area of the rectangle - Area of the semicircle
Area of the rectangle = Length × Width
Length of the rectangle = AD = 8 cm
Width of the rectangle = OP = 4 cm [OP, OB and OC are the radii of the circle which are equal in measures]
Area of the rectangle = 8 × 4 = 32 cm²
Area of the semicircle = 
= 
= 
= 25.12 cm²
Area of the shaded region = 32 - 25.12
= 6.88 cm²