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3 years ago

12

The sixth grade has collected $116 for a local animal shelter. Thief goal is to collect $500. They have three weeks left how muc

h money must theycollect each

2 answers:

leva [86]3 years ago

8 0

500 - 116 = 384 left to collect

384 divided into 3 weeks = 128

They must collect $128 per week in order to reach their goal of $500.

Kipish [7]3 years ago

8 0

Answer:

They must collect 128$ per week

Step-by-step explanation:

Goal of sixth grade for collection = 500$

Money they are collected = 116$

Amount to be collected = 500 - 116 = 384$

Time remaining to collect = 3 weeks

Money needed to be collected per week

$=\frac{384}{3} =128$

So they must collect 128$ per week

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A movie theater sold 800 tickets and made $4400 in one night. If an adult ticket costs $8 and a children's ticket costs $4, how

zhenek [66]

Let x = adult tickets
Let y = children's tickets

x + y = 800
8x + 4y = 4,400

From the first eq, x = 800 - y, plug this in to the second eq
8(800-y) + 4y = 4,400
6400 - 8y + 4y = 4,400
2000 = 4y
500 = y

x = 800 - 500
x = 300

300 adult tickets were sold.

4 0

3 years ago

A flat circular plate has the shape of the region x squared plus y squared less than or equals 1.The plate, including the bound

rjkz [21]

Answer:

We have the coldest value of temperature $T(\frac{3}{4},0) = -9/16$ . and the hottest value is $T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$ .

Step-by-step explanation:

We need to take the derivative with respect of x and y, and equal to zero to find the local minimums.

The temperature equation is:

$T(x,y)=x^{2}+2y^{2}-\frac{3}{2}x$

Let's take the partials derivatives.

$T_{x}(x,y)=2x-\frac{3}{2}=0$

$T_{y}(x,y)=4y=0$

So, we can find the critical point (x,y) of T(x,y).

$2x-\frac{3}{2}=0$

$x=\frac{3}{4}$

$4y=0$

$y=0$

The critical point is (3/4,0) so the temperature at this point is: $T(\frac{3}{4},0)=(\frac{3}{4})^{2}+2(0)^{2}-(\frac{3}{2})(\frac{3}{4})$

$T(\frac{3}{4},0)=-\frac{9}{16}$

Now, we need to evaluate the boundary condition.

$x^{2}+y^{2}=1$

We can solve this equation for y and evaluate this value in the temperature.

$y=\pm \sqrt{1-x^{2}}$

$T(x,\sqrt{1-x^{2}})=x^{2}+2(1-x^{2})-\frac{3}{2}x$

$T(x,\sqrt{1-x^{2}})=-x^{2}-\frac{3}{2}x+2$

Now, let's find the critical point again, as we did above.

$T_{x}(x,\sqrt{1-x^{2}})=-2x-\frac{3}{2}=0$

$x=-\frac{3}{4}$

Evaluating T(x,y) at this point, we have:

$T(-(3/4),\sqrt{1-(-3/4)^{2}})=-(-\frac{3}{4})^{2}-\frac{3}{2}(-\frac{3}{4})+2$

$T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$

Now, we can see that at point (3/4,0) we have the coldest value of temperature $T(\frac{3}{4},0) = -9/16$ . On the other hand, at the point $-(3/4),\frac{\sqrt{7}}{4})$ we have the hottest value of temperature, it is $T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$ .

I hope it helps you!

4 0

2 years ago

Tyra is laying down square carpet pieces in her photography studio. Each square carpet piece is 1 yard by 1 yard. If Tyra's phot

irakobra [83]

Studio = 7 yards by 4 yards

Area = 7*4 = 28 square yards.

Area of square carpet = 1 yard * 1 yard = 1 square yard

Number needed = Area of studio / Area of square carpet = 28 / 1 = 28

Number needed = 28

3 0

3 years ago

This is my last question I need to do what’s the answer

MAXImum [283]

Step-by-step explanation:

According to the question,

l+5=2h

5 0

3 years ago

I wanna know what is -5(2)?

lubasha [3.4K]

the answer is negative ten
-10

4 0

3 years ago

Read 2 more answers