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tamaranim1 [39]
2 years ago
12

What is the mode of this data set? (41,43,3,11,23,24,27,29,45,12,19,22,25)

Mathematics
1 answer:
kodGreya [7K]2 years ago
7 0

Answer:

no mode

Step-by-step explanation:

there is no mode in this data set

this is because there is no number that repeats itself making no number have more quantities than another number

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Kindly answer this one. Thank you.​
steposvetlana [31]

Answer:

See below.

Step-by-step explanation:

I'm assuming these questions are about the Midline Theorem (segment AL joins the midpoints of the non-parallel sides.

♦  The midline's length is the average of the lengths of the top and bottom parallel sides.

AL=\frac{OR+CE}{2}

Use this equation and substitute values given in each problem, then solve for the missing information.

1. AL = x, CE = 9, OR = 5

x=\frac{9+5}{2}=7

2. AL = <em>m</em> - 4, CE = 15, OR = 17

m-4=\frac{15+17}{2}=16\\\\m-4=16\\\\\\m=20\\\\AL=20-4=16

3. OR = y + 5, AL = 15, CE = 18

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4 0
3 years ago
The points (0, 5) and (4, 13) lie on the graph of a linear function. What is the rate of change of the function? Enter your answ
Lorico [155]
Rate of change is the slope...the slope is:
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7 0
3 years ago
Find the equivalent expression of 6^-7
Neporo4naja [7]

Answer:

<h2>11</h2>

Step-by-step explanation:

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3 0
3 years ago
The "mammals" data set in the "MASS" library contains the result of a study of sleep in mammal species. 1 2 Load the "mammals" d
dusya [7]

Complete Question:

The complete question is shown on the first uploaded image

Answer:

The probability that the random you randomly select species that are greater than 200 kg is  = 7/62

Step-by-step explanation:

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data(mammals,package="MASS")

attach(mammals)

Step 2 : Obtain the list of the species that are greater than 200  and store it on y variable.

y <- subset(mammals,body>200)

Step Three : Obtain the total size

nrow(mammals)

Step Four : Obtain the  sum of species greater than 200

sum(body > 200)

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hence

required probability = 7/62

7 0
3 years ago
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