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Likurg_2 [28]
2 years ago
9

A woman is heterozygous for a rare dominant autosomal genetic disease, neurofibromatosis. she marries a normal man (homozygous r

ecessive for neurofibromatosis), who has red-green color blindness, an x-linked recessive trait. they have children. what is the phenotype ratio for the neurofibromatosis gene? a. 1:2:1 b. 1:0 c. 3:1 d. 1:1
Biology
1 answer:
Kazeer [188]2 years ago
6 0

A woman that is heterozygous for neurofibromatosis and a normal man (homozygous recessive for neurofibromatosis) will exhibit a 1:1 phenotype ratio in offspring (Option d).

<h3>What is a rare dominant autosomal genetic disease?</h3>

A rare dominant autosomal genetic disease is a condition inherited in a dominant pattern in very low frequency in the population.

Dominant autosomal genetic diseases are expressed in a 1:1 ratio because they are localized in autosomal (somatic) chromosomes instead of X and Y chromosomes.

In conclusion, a woman that is heterozygous for neurofibromatosis and a normal man (homozygous recessive for neurofibromatosis) will exhibit a 1:1 phenotype ratio in offspring (Option d).

Learn more about dominant autosomal genetic diseases here:

brainly.com/question/17465455

#SPJ1

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