Question

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Answer 1

The coordinates of the triangle A'B'C' are A'(x, y) = (- 4, 0), B'(x, y) = (- 6, 3) and C'(x, y) = (- 2, 5), respectively.

What are the coordinates of the image of the triangle by using a rotation rule?

In this problem we find the coordinates of the three vertices of the triangle and we must determine the coordinates of the image after rotating around the origin 90° counterclockwise. Given a point P, the coordinates of the point P' are calculated by the following expression:

P'(x, y) = (x · cos θ - y · sin θ, x · sin θ + y · cos θ)

Where:

• (x, y) - Coordinates of the point P.
• θ - Angle of rotation, in degrees.

Now we proceed to find the vertices of the new triangle:

A'(x, y) = (0 · cos 90° - 4 · sin 90°, 0 · sin 90° + 4 · cos 90°)

A'(x, y) = (- 4, 0)

B'(x, y) = (3 · cos 90° - 6 · sin 90°, 3 · sin 90° + 6 · cos 90°)

B'(x, y) = (- 6, 3)

C'(x, y) = (5 · cos 90° - 2 · sin 90°, 5 · sin 90° + 2 · cos 90°)

C'(x, y) = (- 2, 5)

To learn more on rotations: brainly.com/question/1571997

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