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lilavasa [31]
3 years ago
8

Choose the simplified form of the fifth term of the expansion. -60x2y8 -30x2y8 30x2y8 60x2y8

Mathematics
2 answers:
alexdok [17]3 years ago
8 0

Answer:

D

Step-by-step explanation:

i just did it

Vika [28.1K]3 years ago
5 0

Answer:

Answer is D on edge

Step-by-step explanation:

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What is the center and radius of the circle with the given equation (x-1)^2+(y+1)^2=4?
Mrrafil [7]
<span>The center is x = 1, y = -1.
The radius is 2. </span>
4 0
3 years ago
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At the football game you buy 2 admission tickets for 3.50 each and some buckets of popcorn for your friends. Each bucket costs $
Alik [6]

Answer:for the admission tickets you spend 7.00 dollars minus 27 equals 20 you have 20 dollars left over so you can only buy 4 buckets

Step-by-step explanation:

4 0
3 years ago
The low temperatures for Anchorage, Alaska last week were: -17°F, 8°F, -9°F, -11°F, 12°F, -13°F, and 2°F. What was the average l
Mademuasel [1]

Answer:

-4 degrees Fahrenheit

Step-by-step explanation:

(-17 +8 + -9 + -11 +12 + -13 +2) / 7 = -4

4 0
3 years ago
Diagram shows a section of a bridge between the points A and K. The length of line segment is 640 meters. ∆ABC, ∆CDF, and ∆FJK a
Marta_Voda [28]
AK = 640
Δ ABC and ΔFJK are similar. They are small triangles.
ΔCDF is the big triangle.

640 / 2 = 320 m= CF
AC & FK= 320/2 =  160 m each

2AC = CF = 2FK
2(160) = 320 = 2(160)

BG = 20 m

20/160 = x / 320
20*320 = 160x
6400 = 160x
6400/160 = x
40 = x

Area of CDF = (40 m * 320 m)/2 = 12,800 / 2= 6,400 m²
3 0
3 years ago
A random sample of 84 students at a university showed an average age of 22 years and a sample standard deviation of 3 years. Fin
Debora [2.8K]

Answer:

The margin of error for the 94% confidence interval is 0.6154.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population mean is:

CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

The margin of error of this interval is:

MOE=z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

The critical value of <em>z</em> for 94% confidence level is, <em>z</em> = 1.88.

Compute the margin of error for the 94% confidence interval as follows:

MOE=z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

          =1.88\times\frac{3}{\sqrt{84}}\\\\=0.6154

Thus, the margin of error for the 94% confidence interval is 0.6154.

7 0
3 years ago
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