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Sergio039 [100]
3 years ago
13

Total

Mathematics
1 answer:
Semmy [17]3 years ago
7 0

Answer:

IBHBHIBH

Step-by-step explanation:

HBHBJBHKJ

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which of the following ordered pairs could be placed in the table below and still have the relation qualify as a linear function
mr_godi [17]
(1,31)
Subtract 2 from x, add 8 to y
8 0
2 years ago
4-2 1/4 <br> as a fraction !!!<br> ill mark !!<br> have a good day !!
noname [10]

Answer:

3/4

Step-by-step explanation:

it's for sure 3/4!!!!!

7 0
3 years ago
I need help asap plz
Lostsunrise [7]

Answer:

A

Step-by-step explanation:

The constant of proportionality is the ratio between the two proportional variables in a directly proportional relationship. In this case, the variables are x and y.

To find the constant of proportionality, all we have to do is divide any value of y by its corresponding value of x. Let's take the values in the first row of the table. We know that x=2 and y=12, so the constant of proportionality is \frac{y}{x}=\frac{12}{2} =6. Hope this helps!

7 0
2 years ago
Tyler buys 3 cans that each contain 3 quarts of blue paint, and he buys 1 can that contains 2 quarts of white paint. What is the
Serga [27]
Tyler has 3 cans of blue paint. Each contains 3 quarts separately. What you need to do is multiply 3 and 3, which would total to 9 quarts. Since you need to include exponents, I´m guessing 3 cubed (3 to the third power) will work. He also buys 1 can of white paint, which only contains 2 quarts. You should add that to the 9 quarts we got from the last steps. I am not sure if this answer is entirely correct, but my guess is 3^3 + 2 = 11 quarts.
6 0
2 years ago
Read 2 more answers
Find all of the points of the form (x −1) which are 4 unit from the point (3,2)
Bond [772]

Answer:

(3+2\sqrt{2},2+2\sqrt{2}),(3-2\sqrt{2},2-2\sqrt{2})

Step-by-step explanation:

Points\ are\ of\ the\ form\ (x,x-1)\\\\Distance\ of\ these\ points\ from\ (3,2)=4\\\\\sqrt{(x-3)^2+(x-3)^2}=4\\\\\sqrt{(x-3)^2+(x-1-2)^2}=4\\\\\sqrt{2(x-3)^2}=4\\\\2(x-3)^2=16\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ square\ both\ the\ sides\\\\(x-3)^2=\frac{16}{2}\\\\(x-3)^2=8\\\\(x-3)=\pm 2\sqrt{2}\ \ \ \ \ \ \ \ \ \ \ square\ root\ both\ the\ sides\\\\x=3\pm 2\sqrt{2}\\\\When\ x=3+2\sqrt{2}\ \ \Rightarrow x-1=3+2\sqrt{2}-1=2+2\sqrt{2}\\\\When\ x=3-2\sqrt{2}\ \ \Rightarrow x-1=3-2\sqrt{2}-1=2-2\sqrt{2}

4 0
2 years ago
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