Question

Which equation represents a circle centered at (3,5) and passing through the

Answer 1

The equation of the circle centered at (3,5) and passing through point (-2,9) is given by:

(x - 3)² + (y - 5)² = 41.

What is the equation of a circle?

The equation of a circle of center $(x_0, y_0)$ and radius r is given by:

$(x - x_0)^2 + (y - y_0)^2 = r^2$

For the circle graphed, we have that the circle is at (3,5), hence $x_0 = 3, y_0 = 5$.

Then:

(x - 3)² + (y - 5)² = r²

The line passes through point (-2,9), that is, when x = -2, y = 9, hence the radius is found as follows:

(x - 3)² + (y - 5)² = r²

r² = (-2 - 3)² + (9 - 4)²

r² = 41.

Hence the equation is:

(x - 3)² + (y - 5)² = 41.

More can be learned about the equation of a circle at brainly.com/question/24307696

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