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Lina20 [59]
3 years ago
8

Isaiah brought two dozen dounts to a class party. Half of the donuts had vanilla frosting with sprinkles, 2 had strawberry, fros

ting with cream filling, and the rest had choclate frosting with spinkles. What fraction of the donuts had sprinkles?
Mathematics
2 answers:
Svetllana [295]3 years ago
3 0

Answer:

10/12= 5/6 simplified.

Step-by-step explanation:


Lera25 [3.4K]3 years ago
3 0
22/24
Since there is 24 donuts total
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6. I think the answer is H, could you help and check?!
Sliva [168]
Set up an equation to solve.
70% of original price equals $550, the amount Susan is paying.
0.70x = 550
8 0
3 years ago
Read 2 more answers
1. SOCCER Suppose a youth soccer field has a
padilas [110]

Answer:

L = 100

W = 60

Step-by-step explanation:

2L + 2W = 320

-2L + 2W = -80

4W = 240

W = 60

L - W = 40

L - 60 = 40

L = 100

6 0
3 years ago
If g(x) = 4x2 - 16 were shifted 9 units to the right and 1 down, what would the new equation be? A. h(x) = 4(x + 9)2 – 17
ArbitrLikvidat [17]

Answer:

Step-by-step explanation:

If you move down 1 unit, you simply subtract 9 units from the given equation.

g(x) = 4x^2 - 16 - 1

g(x) = 4x^2 - 17

Shifting right is a little bit tricky. To shift right, you have to do the opposite of what you would do on the number line. The x has to become x - 9 because the x value (you will learn later) is part of a distance and distances always subtract one from the other.

The wrong way to do it is in answer A.

B is the correct answer

h(x) = 4(x - 9)^2 - 17

6 0
3 years ago
Please help me I will mark u as brainlist​
vitfil [10]

Answer:

What kind of question is it?

5 0
3 years ago
State the domain restriction(s) in interval notation of \displaystyle f\left(g\left(x\right)\right)f(g(x)) given: \displaystyle
DENIUS [597]

Answer:

The interval notation for the domain is [\frac{23}{3},\infty  ].

Step-by-step explanation:

Consider the provided information.

It is given that \:f\left(x\right)=\sqrt{3x-2},\:\text{ and }\:g\left(x\right)=x-7

We need to find the value of f\left(g\left(x\right)\right).

Put the value of g(x) in  f\left(g\left(x\right)\right).

f\left(g\left(x\right)\right)=f(x-7)  ....(1)

Now, put x=x-7 in \:f\left(x\right)=\sqrt{3x-2}

\:f\left(x-7\right)= \sqrt{3(x-7)-2}

\:f\left(x-7\right)= \sqrt{3x-21-2}

\:f\left(x-7\right)= \sqrt{3x-23}

From equation 1.

f\left(g\left(x\right)\right)=\:f\left(x-7\right)= \sqrt{3x-23}

The domain of the function is the set of input values for which a function is defined.

Here, the value of 3x-23 should be greater or equal to 0 as the square root of a negative number is not real.

Domain= 3x-23\geq0

x\geq\frac{23}{3}

The value of x is all real number greater than \frac{23}{3}.

Hence, the interval notation for the domain is [\frac{23}{3},\infty  ].

7 0
3 years ago
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