The coordinates of point Q are (-2, -3). In which quadrant isQ?

Mathematics

2 answers:

Archy [21]2 years ago

4 0

Quadrant I : (+ , +)
quadrant II : (- , +)
quadrant III : (- , -)
quadrant IV : (+ , -)

so that means Q (-2,-3) is in quadrant III

mihalych1998 [28]2 years ago

3 0

Point Q is in quadrant 3.

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Find m angle QSRIf m angle TSQ=15x , m angle TSR=173^ , and m angle QSR=10x-2

Serggg [28]

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$\small\color{blak}{{\underline{\bold{ Find \:a X } } } }$

$\small\color{black}{{\underline{\bold{173°=15z+10x-2 } } } } \\ = 173 = 25x - 2 \\ = - 25x = - 2 - 173 \\ = - 25x - 175 \\ = \small\color{blue}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\: x=7\:\:\:\: }}}}$

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$\small\color{blak}{{\underline{\bold{ 10(7)-2 } } } }\\=70-2\\=\small\color{red}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\: m$

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2 years ago

www.g The physical plant at the main campus of a large state university recieves daily requests to replace fluorescent lightbulb

damaskus [11]

Answer:

$z=\frac{24-40}{8}=-2$

$z=\frac{40-40}{8}=0$

And then the percentage between 24 and 40 would be $\frac{95}{2}= 47.5 \%$

Step-by-step explanation:

For this problem we have the following parameters given:

$\mu = 40, \sigma =8$

And for this case we want to find the percentage of lightbulb replacement requests numbering between 24 and 40.

From the empirical rule we know that we have 68% of the values within one deviation from the mean, 95% of the values within 2 deviations and 99.7% within 3 deviations.

We can find the number of deviations from themean for the limits with the z score formula we got:

$z=\frac{X-\mu}{\sigma}$