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2 years ago

The equation f(x)=x−5 translated 4 units to the left is g(x)=

Mathematics

1 answer:

elixir [45]2 years ago

3 0

The equation of the function g(x) is g(x) = x - 1

<h3>How to determine the equation of the function g(x)?</h3>

The given parameters are:

f(x) = x - 5

The above function f(x) is translated left by 4 units

So, we have

g(x) = f(x + 4)

This gives

f(x + 4) = x + 4- 5

Evaluate the sum

f(x + 4) = x - 1

So, we have:

g(x) = x - 1

Hence, the equation of the function g(x) is g(x) = x - 1

Read more about function transformation at:

brainly.com/question/10904859

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16. A necklace of former First Lady Jacqueline Kennedy Onassis was originally worth $700. Its

marusya05 [52]

Answer:

30,114.3%

Step-by-step explanation:

Use the percent increase formula:

((new value - initial value) / initial value) x 100

Plug in the values:

((211,500 - 700) / 700) x 100

(210,800 / 700) x 100

= 30,114.29

So, the percent increase is 30,114.3%

6 0

3 years ago

Read 2 more answers

Find the hypotenuse of each isosceles right triangle when the legs are of the given measure. 6 sqrt 2

Gemiola [76]

Isosceles right triangles have two equal sides (a and b) that are not the hypotenuse (c). And when two sides are equal, so are their opposite angles. There are only 180° degrees in any triangles, thus the right angle = 90°, so 90 left for the two equal, means that 2x=90,
x = 45°.

There are several ways to go about solving a triangle like this. The best and easiest is simply to memorize that the hypotenuse is exactly root2 times the other sides. Or, each isosceles side is the hypotenuse (c) ÷ root2
$a = b = c \div \sqrt{2} \\ c = a\sqrt{2} \\ c = 6 \sqrt{2} \times \sqrt{2} = 6 \times 2 = 12$
Another way to do it is the longer proof of Pythagorean Theorem:
${c}^{2} = {a}^{2} + {b}^{2}... \: \: c = \sqrt{({a}^{2} + {b}^{2})} \\$
$c= \sqrt{({6 \sqrt{2}) }^{2} + ({6 \sqrt{2})}^{2}} \\ = \sqrt{(2 \times{(6 \sqrt{2} )}^{2} )} = \sqrt{2(36 \times 2)} \\ c = \sqrt{144} = 12$

7 0

3 years ago

What is the domain of y=4sin(x)?

stealth61 [152]

Answer:

( − ∞ , ∞ ) { x | x ∈ R }

Step-by-step explanation:

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

4 0

3 years ago

Translate 2/3 y − 9 < y + 1 into a sentence

erma4kov [3.2K]

Answer: Nine less than two thirds of a quantity is smaller than one more than that same quantity.

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3 years ago

Jay factored the 4 term polynomial : x^3 - 9x +2x^2 - 18 and decided that the complete factorization was : ( x + 2 ) (x^2-9 ). B

labwork [276]

Answer:

$x^3-9x+2x^2-18\left(x+2\right)\left(x+3\right)\left(x-3\right)$

Step-by-step explanation:

we are given that $x^3-9x+2x^2-18$

w are sked to step by step factorise the above polynomial

$\left(x^3+2x^2\right)+\left(-9x-18\right)$

$-9\mathrm{\:from\:}-9x-18\mathrm{:\quad }-9\left(x+2\right)$

$-9x-9\cdot \:2$

$-9\left(x+2\right)$

$\mathrm{Factor\:out\:}x^2\mathrm{\:from\:}x^3+2x^2\mathrm{:\quad }x^2\left(x+2\right)$

$-9\left(x+2\right)+x^2\left(x+2\right)$

$\left(x+2\right)\left(x^2-9\right)$

$x^2-9:\quad \left(x+3\right)\left(x-3\right)$

$x^2-9$

$\mathrm{Rewrite\:}9\mathrm{\:as\:}3^2$

$=x^2-3^2$

$\mathrm{Apply\:Difference\:of\:Two\:Squares\:Formula:\:}x^2-y^2=\left(x+y\right)\left(x-y\right)$

$x^2-3^2=\left(x+3\right)\left(x-3\right)$

Hence

$x^3-9x+2x^2-18=\left(x+2\right)\left(x+3\right)\left(x-3\right)$

a) The jay mistake was he did not factorise $x^3-9x+2x^2-18x^2-9 furtherb) the complete answer wil be [tex]x^3-9x+2x^2-18\left(x+2\right)\left(x+3\right)\left(x-3\right)$

8 0

3 years ago

Read 2 more answers