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tresset_1 [31]
3 years ago
11

Two integers whose product is 90 and whose sum is 21

Mathematics
2 answers:
Likurg_2 [28]3 years ago
8 0

Answer:

6 and 15

Step-by-step explanation:

Leni [432]3 years ago
5 0

Answer:

6 and 15

Step-by-step explanation:

the factors of 90 are:

1   90

2   45

3   30

5   18

6   15

9   10

find the factors that =21

6+15=21 and 6 x 15=21

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What is the polynomial function of lowest degree with lead coefficient 1 and roots i, -2 and 2?
lutik1710 [3]

Answer:

Step-by-step explanation:

the polynomial function is;  (x - i)(x-2)(x+2)

7 0
3 years ago
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If g(x)=x+1/x-2 and h(x)=4-x what is the value of (g•h)(-3)
djyliett [7]

The Answers is


g(x) = (x + 1)/(x - 2)

h(x) = 4 - x


g(h(x)) = (4 - x + 1)/(4 - x - 2) = (5 - x)/(2 - x)


g(h(-3)) = (5 - (-3))/(2 - (-3)) = (5 + 3)/(2 + 3) = 8/5


g(h(-3)) = 8/5.

3 0
3 years ago
What is the prime factorization of 36?<br><br> 2 ²× 9<br> 2 × 3²<br> 2² × 3²<br> 3 × 13
evablogger [386]

Answer:

2 squared  times 3 squared

Step-by-step explanation:

4 0
3 years ago
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What is the value of x in the equation 8 + 4 = 2 (x minus 1)?
satela [25.4K]

Answer:

x= 7

Step-by-step explanation:

The equation is 8+4= 2(x-1)

Distribute into the parenthesis.

8+4= 2x-2

Now, add.

12= 2x-2

Add 2 to both sides.

12= 2x-2

+2       +2

Then, divide by 2 to both sides to isolate the variable.

<u>14</u>= <u>2x</u>

2    2

x=7

6 0
3 years ago
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Are AB and CD parallel, perpendicular, or neither?*<br> 1. A(-4, 8), B(4, 10), C(1, 1), D(-2, 13)
ohaa [14]

Answer:

Perpendicular

<em />

Step-by-step explanation:

Given

A = (-4, 8)

B = (4, 10)

C = (1, 1)

D = (-2, 13)

Required

Is AB and CD parallel?

First, we need to calculate the slope (m) of AB and CD

m = \frac{y_2 - y_1}{x_2 - x_1}

For AB:

A (x_1,y_1)= (-4, 8)

B(x_2,y_2) = (4, 10)

So:

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{10 - 8}{4 - (-4)}

m = \frac{10 - 8}{4 +4}

m = \frac{2}{8}

m = \frac{1}{4}

For CD:

C(x_1,y_1) = (1, 1)

D(x_2,y_2) = (-2, 13)

So:

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{13 - 1}{-2 - 1}

m = \frac{12}{-3}

m = -4

For Lines to be parallel, the slope must be equal:

i.e. m_1 = m_2

This condition is not true because:

\frac{1}{4} \neq -4

For Lines to be perpendicular, the slope must be:

m_1 = -\frac{1}{m_2}

This implies:

\frac{1}{4} = -\frac{1}{-4}

\frac{1}{4} = \frac{-1}{-4}

\frac{1}{4} = \frac{1}{4}

<em>Hence, the lines are perpendicular</em>

6 0
3 years ago
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