First you plot in the y-intercept of the equation. To find the y-intercept, substitute 0 into x. -3m will cancel our giving you y=5. x=0, y=5, the first ordered pair is (0,5). Now after you plot in the y-intercept, use your slope, which is -3, to graph the points of the equation. Starting from (0,5), move down 3 spaces on the y-axis (because it’s -3) and you’ll end up at (0,2). Next move over 1 ( all slopes with just a whole number moves on the x-axis 1 since the whole number divided by 1 doesn’t change the slope number) to the right because it’s a negative linear equation so it’ll go downward. After moving right, you’ll get (1,2). Do a couple more points starting from (1,2) then the 3rd point ABD and so on to get 3 or more points to be able to draw a linear line.
I think that it the secound one then the fourth one then the sixth one then the first one then the fifth one then third one the eighth one then the ninth one
After 5 tests, her average was 88. To have a seven-test average of 90, the total must be:
Her average after 5 tests was 88. Her total score on the 5 tests is:
Subtract:
Find the average by dividing by 2:
Her average must be 95
3(-3 + 5x) -1 (4 - 4x)
Simplify each term by first using the distributive property with each set of parenthesis:
3*-3 + 3*5x - 1*4 -1* -4x
Now do the multiplications:
-9 + 15x -4 + 4x
Combine like terms
15x +4x - 9 -4
19x - 13
