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ladessa [460]
1 year ago
6

Please help

Mathematics
1 answer:
Svetllana [295]1 year ago
8 0

The midpoint of the line segment joining points S (8,3) and T (2,-1) is (5, 1)

<h3>How to determine the midpoint of the line segment joining the points?</h3>

The points are given as:

S(8,3) and T(2,-1)

The midpoint of the line segment joining points S(8,3) and T(2,-1) is calculated as:

Midpoint = 0.5 * (x1 + x2, y1 + y2)

So, we have

Midpoint = 0.5 * (8 + 2, 3 - 1)

Evaluate the sum

Midpoint = 0.5 * (10, 2)

Evaluate the product

Midpoint = (5, 1)

Hence, the midpoint of the line segment joining points S (8,3) and T (2,-1) is (5, 1)

Read more about midpoint at:

brainly.com/question/24311350

#SPJ1

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Finish the pattern<br> 18, 21, _ , 24, _ , 30
omeli [17]
Goes +3 
18, 21, 24, 27, 30
4 0
3 years ago
Read 2 more answers
How do i do this. will give brainliest
Tomtit [17]

Try this option ↓

Step-by-step explanation:

1) according to the condition two angles are equal, then two sides are equal also, it means

2) √x+4=√(5x+4);

3) the 'x' can be calculated if to solve this equation:

\sqrt{x} +4=\sqrt{5x+4};

x+16+8\sqrt{x} =5x+4;

4x-12=8\sqrt{x} ;\ => \ x-2\sqrt{x} -3=0;

\left \{ {{\sqrt{x} =-1} \atop {\sqrt{x} =3}} \right. \ => \ x=9.

4) finally, answer: 9.

4 0
2 years ago
How do I solve question 6 through 8?<br> Solve for me
rewona [7]

The equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

<h3>How to determine the functions?</h3>

A quadratic function is represented as:

y = a(x - h)^2 + k

<u>Question #6</u>

The vertex of the graph is

(h, k) = (-1, 2)

So, we have:

y = a(x + 1)^2 + 2

The graph pass through the f(0) = -2

So, we have:

-2 = a(0 + 1)^2 + 2

Evaluate the like terms

a = -4

Substitute a = -4 in y = a(x + 1)^2 + 2

y = -4(x + 1)^2 + 2

<u>Question #7</u>

The vertex of the graph is

(h, k) = (2, 1)

So, we have:

y = a(x - 2)^2 + 1

The graph pass through (1, 3)

So, we have:

3 = a(1 - 2)^2 + 1

Evaluate the like terms

a = 2

Substitute a = 2 in y = a(x - 2)^2 + 1

y = 2(x - 2)^2 + 1

<u>Question #8</u>

The vertex of the graph is

(h, k) = (1, -2)

So, we have:

y = a(x - 1)^2 - 2

The graph pass through (0, -3)

So, we have:

-3 = a(0 - 1)^2 - 2

Evaluate the like terms

a = -1

Substitute a = -1 in y = a(x - 1)^2 - 2

y = -(x - 1)^2 - 2

Hence, the equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

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5 0
1 year ago
The two polygons above are similar. The scale factor of the smaller polygon to the larger polygon is 3. The area of the smaller
Softa [21]
You would think it was 3 * 12 = 36. Not so. All polygons have to be broken down into some figure that will give 2 dimensions that are at right angles to each other. That would mean that
d1 * d2 = Area for the small polygon
3d1 * 3d2 = area of the larger polygon

What that means is that the area of the larger one is 9 times the smaller one.
Area large = 12 * 9 = 108 square units. <<<<< answer.

If you find this hard to be leave try it with a square.
Suppose you have a square (the small one) that is 3 cm by 3 cm
The small one has an area of 3*3 cm^2 = 9 cm

Now you have another square that is 3 times larger. That means that each side is 3*3 = 9
So s = 9
Area = s^2
Area = 9^2 = 81 cm^2
81 is 9 times larger than 9 just as you would think. 


4 0
3 years ago
0.327 rounded to the nearest hundredths
daser333 [38]
.33 because the 2 needs to round up hecause there is a number greater than 5 after it
8 0
3 years ago
Read 2 more answers
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