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Margarita [4]
3 years ago
5

Lol I need the answer please

Mathematics
1 answer:
liberstina [14]3 years ago
4 0

Answer: The last one

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What is this answer16a2-4b
natima [27]

Answer:

= 4(4 {a}^{2}  - b)

Step-by-step explanation:

16 {a}^{2}  - 4b

= 4(4 {a}^{2}  - b)

7 0
3 years ago
By writing sin 3x = sin(2x+x), show that sin 3x = 3 sin x - 4 sin^3 x.
Ksju [112]

Given the trigonometry expression:

sin 3x = sin(2x+x),

In trigonometry identity;

Sin(A+B) = sinAcosB + cosAsinB

The expression above will then become;

sin(2x+x) =sin2xcosx+cos2xsinx\\sin(2x+x) =2sinxcosxcosx + (1-2sin^2x)sinx\\sin(2x+x) =2sinxcos^2x + (1-2sin^2x)sinx\\

Recall that sin^2x + cos^x = 1, hence;

sin(2x+x) =2sinx(1-sin^2x)+ (1-2sin^2x)sinx\\Expand\\sin(2x+x) =2sinx-2sin^3x+ sinx-2sin^3x\\sin(2x+x) =2sinx + sinx-2sin^3x-2sin^3x\\sisn(2x+x) = 3sinx-4sin^3x

This shows that sin3x =3sinx-4sin^3x (Proved!)

Learn more here: brainly.com/question/7331447

8 0
3 years ago
See image for question.<br><br>Please show workings and diagrams.​
Komok [63]

Answer:

  • a) 258 km
  • b) 267°
  • c) 87°

Step-by-step explanation:

  • <em>Refer to attached diagram (not to scale).</em>
  • <em>Given details are reflected.</em>

<u>First find the measure of angle Q</u>

  • m∠Q = 36° + (180° - 125°) = 91°

a) <u>Use law of cosines to find x:</u>

  • x = √(160² + 200² - 2160*200*cos 91°) = 258 km (rounded)

<u>Use the law of sines to find the missing angles:</u>

  • 258 / sin 91 = 160 / sin R = 200 / sin P
  • m∠R = arcsin (160 sin 91° / 258) = 38°
  • m∠P = 180° - (91° + 38°) = 51°

b) <u>Bearing P from R:</u>

  • 360° - (55° + 38°) = 267°

c)  <u>Bearing R from P:</u>

  • 36° + 51° = 87°

4 0
3 years ago
Read 2 more answers
Hannah spent 40% of the money she earned last month. If she spent $50, what was the total amount of money that she earned babysi
gavmur [86]
Let, the amount she earned = x
Then, x * 40% = 50
x * 0.40 = 50
x = 50 / 0.40
x = 125

In short, Your Answer would be Option C

Hope this helps!
8 0
3 years ago
Read 2 more answers
Find the distance and midpoint for (2, 0, -2) and (5, -4, 6)
sweet-ann [11.9K]
Hi, It is well simples:

The distance between two points is :

d( A, B) = √[ (xb - xa)^2+(yb - ya)^2+(zb - za)^2]


Then,

A = (xa, ya, za )

B = (xb , yb , zb)

We know:

A = ( 2 ,0 ,-2)

And,

B = (5 , -4 , 6)
___________

xb - xa = 5-2 <=> 3

yb - ya = -4 - 0 <=> -4

zb - za = 6 - (-2) <=> 8

Then us stay:

d( A, B) = √[ (3)^2 + (-4)^2+(8)^2]

= √( 9 + 16 + 64)

= √( 25 + 64)

= √(89)

7 0
3 years ago
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