(X²-8X+5)-(-3X²+5X-9)
=X²-8X+5+3X²-5X+9
=4X²-13X+14
That's your answer lovely~
Answer:
10/12x100%= 83.3%
Step-by-step explanation:
Answer:
the answer is 2× + 3×
Step-by-step explanation:
hope it helps
Answer:
The position P is:
ft <u><em> Remember that the position is a vector. Observe the attached image</em></u>
Step-by-step explanation:
The equation that describes the height as a function of time of an object that moves in a parabolic trajectory with an initial velocity
is:

Where
is the initial height = 0 for this case
We know that the initial velocity is:
82 ft/sec at an angle of 58 ° with respect to the ground.
So:
ft/sec
ft/sec
Thus

The height after 2 sec is:


Then the equation that describes the horizontal position of the ball is

Where
for this case
ft / sec
ft/sec
So

After 2 seconds the horizontal distance reached by the ball is:

Finally the vector position P is:
ft
I think you count the squares in the middle or radius ?