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geniusboy [140]
3 years ago
9

What is the slope for y=7/2x - 2?

Mathematics
1 answer:
barxatty [35]3 years ago
3 0
Easy peasy
slope intercept form is y=mx+b where m=slope

we see taht we have y=7/2x-2
therefor m=slope=7/2
the slope is 7/2
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7 0
3 years ago
An auctioneer sold a herd of cattle whose minimum weight was 920 ​pounds, median was 1160 ​pounds, standard deviation 76​, and I
katen-ka-za [31]

Answer:

minimum = $445

median = $565

standard deviation = $38

IQR = $48

Step-by-step explanation:

The minimum and the median are measures of location and are affected during addition (or subtraction) and multiplication (or division).

Satandard deviation and IQR (inter-quartile range), which are measures of dispersion, are affected by only multiplication (or division).

For the weight,

<em>minimum </em>= 920 pounds

<em>median </em>= 1160 pounds

<em>standard deviation</em> = 76 pounds

<em>IQR </em>= 96 pounds

For the price,

<em>minimum </em>= 0.50(920) - 15 = $445

<em>median </em>= 0.50(1160) - 15 = $565

<em>standard deviation</em> = 0.50(76) = $38............(<em>Subtraction discarded</em>)

<em>IQR </em>= 0.50(96) = $48........................................(<em>Subtraction discarded</em>)

7 0
3 years ago
Margin of error: 0.009; confidence level: 99%; p and a unknown
mafiozo [28]

Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.009}{2.58})^2}=20544.44  

And rounded up we have that n=20545

Step-by-step explanation:

Assuming this question: Use the data to find minium sample size required to estimate population proportion. Margin of error: 0.009, confidence level: 99%, p and q are unknown.

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.009 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

Assuming an estimation of p as \hat p =0.5. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.009}{2.58})^2}=20544.44  

And rounded up we have that n=20545

7 0
3 years ago
Factor f(x) = 22 - 5x + 6 using any method.<br> -<br> please helppp
ankoles [38]

Answer:

(x-2)(x-3)

Step-by-step explanation:

x^2-5x+6

x^2-3x-2x+6

x(x-3)-2(x-3)

(x-2)(x-3)

6 0
2 years ago
What is 67 squared ? give answers
eduard
Here it is
67^2  = 67*67 = 4489 
7 0
3 years ago
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