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geniusboy [140]
3 years ago
9

What is the slope for y=7/2x - 2?

Mathematics
1 answer:
barxatty [35]3 years ago
3 0
Easy peasy
slope intercept form is y=mx+b where m=slope

we see taht we have y=7/2x-2
therefor m=slope=7/2
the slope is 7/2
You might be interested in
Solve the equation log3(x+24)+log3 x=4
fredd [130]
Log_3(x(x + 24) = 4

log_3(x^2 + 24x) = 4

3^4 = (x^2 + 24x)

81 = x^2 + 24x

x^2 + 24x - 81 = 0

Continue from here.
7 0
3 years ago
A thermometer is removed from a room where the temperature is 70° F and is taken outside, where the air temperature is 40° F. Af
fgiga [73]

Answer:

53.3324

Step-by-step explanation:

given that a  thermometer is removed from a room where the temperature is 70° F and is taken outside, where the air temperature is 40° F.

By Newton law of cooling we have

T(t) = T+(T_0-T)e^{-kt}

where T (t) is temperature at time t,T =surrounding temperature = 40, T0 =70 = initial temperature

After half minute thermometer reads 60° F. Using this we can find k

T(0,5) = 40+(70-40)e^{-k/2} = 60\\e^{-k/2} =2/3\\-k/2 = -0.4055\\k = 0.8110

So equation is

T(t) = 40+(30)e^{-0.8110t}\\

When t=1,

we get

T(1) = 40+(30)e^{-0.8110}\\\\=53.3324

5 0
3 years ago
suppose triangle ABC is reflected over the x-axis. If the distance between point A and the x-axis is 7, what is the distance bet
astra-53 [7]

Answer:

7

Step-by-step explanation:

If A is 7 units away from the x-axis then the x-axis is seven units away from A.

That's if I read the question right.

6 0
3 years ago
if a square with point H at coordinates (-8,5) was reflected across the y-axis, what would the coordinates of point H' be ?
zimovet [89]

Answer:

Your answer would be 8 and 5 because you are just moving the point over the y axis from -8 and 5 to 8 and 5.

Step-by-step explanation:


6 0
3 years ago
Help anyone plezzzzzzzzzzzzzzzzzzz
emmainna [20.7K]
              <span> Direct-substituting x = -2 gives 0/0, so we know that by the factor theorem, both the numerator and denominator have a factor of x + 2. From there, we can cancel out the conflicting factors and apply the limit.

We can factor the numerator and denominator to get:

x^3 - x^2 - x + 10 = (x + 2)(x^2 - 3x + 5)
x^2 + 3x + 2 = (x + 2)(x + 1).

So we have:

lim (x-->-2) (x^3 - x^2 - x + 10)/(x^2 + 3x + 2)
= lim (x-->-2) [(x + 2)(x^2 - 3x + 5)]/[(x + 2)(x + 1)]
= lim (x-->-2) (x^2 - 3x + 5)/(x + 1), by canceling out x + 2
= [2^2 - 3(-2) + 5]/(-2 + 1)
= (4 + 6 + 5)/(-1)
= -15.

I hope this helps! </span>
7 0
3 years ago
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