Can i get a good answer as to how to solve this

Mathematics

1 answer:

Digiron [165]3 years ago

4 0

This is a trick question. DFG is the isosceles right triangle so DGF=FDG=45 degrees. We have triangle DEF congruent to DGF, side-side-side. So EDG=90 degrees, so ADG=90 (they're supplementary). That's the measure of the arc AG.

Answer: 90 degrees

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A glass is

fenix001 [56]

Step-by-step explanation:

x=volume of the glass

(1/3)x+63=(5/8)x

63=(5/8)x-(1/3)x

63=(15/24)x-(8/24)x

63=(7/24)x

multiply both sides by 24/7

(24/7)(63)=(24/7)(7/24)x

216=x

216 cm3 is the volume (answer)

1/3 of 216 is 72

72+63=135

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3 years ago

There are two college entrance exams that are often taken by students, Exam A and Exam B. The composite score on Exam A is appro

elena55 [62]

Answer:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Two exams. The exam that you did score better is the one in which you had a higher zscore.

The composite score on Exam A is approximately normally distributed with mean 20.1 and standard deviation 5.1.

This means that $\mu = 20.1, \sigma = 5.1$ .