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guapka [62]
1 year ago
14

what's the surface area of this square pyramid that has a base length of 5 inches and triangular faces that are 9 inches tall

Mathematics
1 answer:
Vadim26 [7]1 year ago
7 0

The surface area of the square prism is 115 square inches

<h3>surface area of a pyramid</h3>

The surface area of a pyramid is equivalent to the sum of the faces of the pyramid

For the given square pyramid;

TSA = (5*5) + 4(1/2 * 9 * 5)

Simplify to have;

Surface area =25 + 4(45/2)

Surface area = 25 + 180/2

Surface area = 25. + 90

Surface area = 115 square inches

Hence the surface area of the square prism is 115 square inches

Learn more on surface area here: brainly.com/question/20771646

#SPJ1

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Answer:

The remainder is -2.

Step-by-step explanation:

According to the Polynomial Remainder Theorem, if we divide a polynomial P(x) by a binomial (<em>x</em> - <em>a</em>), then the remainder of the operation will be given by P(a).

Our polynomial is:

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We can rewrite our divisor as (<em>x</em> - (-1)). Hence, <em>a</em> = -1.

Then by the PRT, the remainder will be:

\displaystyle\begin{aligned}  R &= P(-1)\\ &=(-1)^3-4(-1)^2-6(-1)-3 \\ &= (-1)-4(1)+(6)-3 \\ &= -2 \end{aligned}

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Ans

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