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Ann [662]
3 years ago
15

The population of a small town, P, as a function of time, t, in years past 1940 is given below.

Mathematics
2 answers:
hjlf3 years ago
6 0

Answer:

1976

Step-by-step explanation:

hope this helps

romanna [79]3 years ago
3 0

Answer: 1976

Steps:

Let t* be the year in which the population reached a count of 8920. Solve for t*:

P=200t+1720\\8920=200t^*+1720\\7200=200t^*\\t^* = 36

The population grew to the number 8920 in 36 years past 1940, i.e., 1976

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Choose the graph which matches the function. (2 points) <br> f(x) = 3x-4
vovangra [49]

The last image is the graph of y = 3^x

In fact, it is an increasing exponential function, and it passes through the points (0,1), which reflects the fact that 3^0=1 and (1,3), which reflects the fact that 3^1=3.

Now, y = 3^{x-4} is a child of the parent function we just described. Precisely, it is the result of the transformation f(x) \to f(x-4)

In general, every time you perform a transformation like f(x) \to f(x+k), you translate the graph horizontall, k units to the left if k is positive, and k units to the right if k in negative.

Since in this case k = - 4, we have a horizontal translation of 4 units to the right.

So, the correct option is the third one, because:

  • The first graph is the parent function translated 4 units to the left
  • The second graph is the parent function translated 4 units down
  • The third graph is the parent function translated 4 units to the right
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5 0
3 years ago
Amy, Bruce and Carlos collected a total of 168 pounds of cans to recycle. Bruce collected 1/3 the number of pounds of cans Carlo
disa [49]
A + b + c = 168
b = 1/3c
a = b + c....a = 1/3c + c = 4/3c

now we sub
4/3c + 1/3c + c = 168
8/3c = 168
c = 168 * 3/8
c = 504/8
c = 63 <=== Carlos collected 63 lbs

a = 4/3c
a = 4/3(63)
a = 252/3
a = 84 <== Amy collected 84 lbs

b = 1/3c
b = 1/3(63)
b = 63/3 <== Bruce collected 21 lbs
b = 21

3 0
2 years ago
Can someone help with this problem on literal equations to get variable A by itself? Will give lots of points
-BARSIC- [3]

Answer:

Step-by-step explanation:

Part A

xf = xo + vo* t + 1/2 a*t^2                    Subtract xo

xf - xo = 0*t + 1/2 a*t^2                        multiply by 2

2(xf - xo) = at^2                                    divide by t^2

2(xf - xo ) / t^2 = a

Part B

Givens

xo =0

vo = 0

a = 10  m/s^2

xf = 120 m

Solution

xf = xo + vo* t + 1/2 a*t^2              Substitute the givens

120 = 0 + 0 + 1/2 * 10 * t^2            Multiply by 2

120*2 = 10* t^2                  

240 = 10*t^2                                  Divide by 10

240/10  = t^2

24 = t^2                                          take the square root of both sides.

√24 = √t^2

t = √24

t = √(2 * 2 * 2 * 3)

t = 2√6

8 0
3 years ago
I need help with #14. I checked on Desmos to see if they represent the same line, which they do. But how do you know if they rep
DaniilM [7]
Put the second equation so it's in y= form, it should be the same :)
7 0
3 years ago
you bought 5 chocolate bars and 8 blow pops for $23.25 your sister bought 2 chocolate bars and 13 blow pops for 21.55 how much d
kirza4 [7]

Answer:

  • $2.65

Step-by-step explanation:

Let chocolate bar = c and blow pops = b

<u>As per given we have equations below:</u>

  • 5c + 8b = 23.25
  • 2c + 13b = 21.55

<u>13 times the first equation minus 8 times the second to eliminate b and find c:</u>

  • 13(5c + 8b) - 8(2c + 13b) = 13(23.25) - 8(21.55)
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  • 49c = 129.85
  • c = 129.85/49
  • c = 2.65

Each chocolate bar costs $2.65

7 0
3 years ago
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