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1 year ago

Factor completely: 5n^2 - 80

Mathematics

2 answers:

grandymaker [24]1 year ago

6 0

Answer:

Step-by-step explanation:

Factoring 5n2-9n-2

The first term is, 5n2 its coefficient is 5 .

The middle term is, -9n its coefficient is -9 .

The last term, "the constant", is -2

Step-1 : Multiply the coefficient of the first term by the constant 5 • -2 = -10

Step-2 : Find two factors of -10 whose sum equals the coefficient of the middle term, which is -9 .

-10 + 1 = -9 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -10 and 1

5n2 - 10n + 1n - 2

Step-4 : Add up the first 2 terms, pulling out like factors :

5n • (n-2)

Add up the last 2 terms, pulling out common factors :

1 • (n-2)

Step-5 : Add up the four terms of step 4 :

(5n+1) • (n-2)

Which is the desired factorization

Vesnalui [34]1 year ago

4 0

Answer:
5(n-4)(n+4)
Step-by-step explanation:
given that
5n²-80
first we take common factor.
5(n²-16)
now we use the sum product pattern
5(n²+4n-4n-16)
We take common factor from pairs
5(n(n+4)-4(n+4))
5(n+4)(n-4).

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