<span>1) 2p = -2.
<span> 4p [ y - k ] = [ x - h) ]² --- > - 4 [ y + 5 ] = [ x + 5 ]²
2) </span></span><span>4p * (y - k) = (x - h)^2 </span>
<span>(h , k) is the vertex </span>
<span>The vertex is halfway between the focus and the directrix (when they're at their closest) </span>
<span>p is that distance </span>
<span>2 - 1 = 1 </span>
<span>4p = 1 </span>
<span>p = 1/4 </span>
<span>(1/4) * (y - k) = (x - h)^2 </span>
<span>y - k = 4 * (x - h)^2 </span>
<span>The vertex is at (6 , 3/2), since that's midway between (6 , 1) and (6 , 2) </span>
<span>y - 3/2 = 4 * (x - 6)^2 </span>
<span>y = (3/2) + 4 * (x - 6)^2
</span><span>
4) </span><span>f(x) = (-1/16)*(x²)
</span><span>
5) </span><span>f(x) = −1/4 x2 − x + 5</span><span>
</span>
Answer:
The mean absolute deviation of the data set is 6
Step-by-step explanation:
To find the mean absolute deviation of the data, start by finding the mean of the data set.
- Find the sum of the data values, and divide the sum by the number of data values.
- Find the absolute value of the difference between each data value and the mean: |data value – mean|.
- Find the sum of the absolute values of the differences.
- Divide the sum of the absolute values of the differences by the number of data values
∵ The data are 68 , 59 , 65 , 77 , 56
- Find their sum
∴ The sum of the data = 68 + 59 + 65 + 77 + 56 = 325
∵ The number of data in the set is 5
- Find the mean by dividing the sum of the data by 5
∴ The mean = 325 ÷ 5 = 65
- Find the absolute difference between the each data and the mean
∵ I68 - 65I = 3
∵ I59 - 65I = 6
∵ I65 - 65I = 0
∵ I77 - 65I = 12
∵ I56 - 65I = 9
- Find the sum of the absolute differences
∵ The sum of the absolute differences = 3 + 6 + 0 + 12 + 9
∴ The sum of the absolute differences = 30
Divide the sum of the absolute differences by 5 to find the mean absolute deviation
∴ The mean absolute deviation = 30 ÷ 5 = 6
The mean absolute deviation of the data set is 6