Amount of interest = 3/100 x 1200
= $36
Answer is B
f(0) = ( f(k) +f(-k) ) / 2
f(0) = (16 - 4) / 2
f(0) = 12 / 2
f(0) = 6 → ANSWER
*Remember that f(0) = m(0) + n = n
If we have f(x) = mx + n, then:
f(k)= mk + n and f(-k)= -mk + n
If we add them:
f(k) + f(-k)
= mk + n -mk + n
= 2n
= 2f(0)
So we conclude that:
f(0) = [f(k) + f(-k)] / 2
2.8 because 14/5 equals 2 80/100.
Answer:
10(5x - 6).
8(2m + 5).
9(3 - 5c)
Step-by-step explanation:
Given that
50x-60
16m+40
27-45c
The greatest common factor is a measure of the highest number present inside, or common to all the numbers that were listed. To take this one at a time, we have....
50x - 60. The highest number common to both of them is 10, and thus, we have
50x - 60 = 10(5x - 6), and this is the solved part.
16m + 40. The greatest number that's present inside both numbers is 8, and thus we have
16m + 40 = 8(2m + 5) and this is the solved part.
27 - 45c. The greatest common number is 9, and as a result, we have
27 - 45c = 9(3 - 5c), and this is the solution we were searching for
Answer + Step-by-step explanation:
(a)
Check the attached image.
(b)
Range of sample means : 7.5 - 5.75 = 1.25
(c)
The closer the range of the sample means is to 0 ,
the more confident they can be in their estimate . 
The farther the range of the sample means is from 0 ,
the more confident they can be in their estimate .
The mean of the sample means will tend to be a better estimate
than a single sample mean . 
A single sample mean will tend to be a better estimate
than the mean of the sample means .