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Diano4ka-milaya [45]
3 years ago
10

If

7Bb%7D" id="TexFormula1" title=" \sqrt{0.3+ \sqrt{0.08} } = \sqrt{a} + \sqrt{b}" alt=" \sqrt{0.3+ \sqrt{0.08} } = \sqrt{a} + \sqrt{b}" align="absmiddle" class="latex-formula"> Then 1/a + 1/b = ....
I Hope Someone Answer My question
Mathematics
1 answer:
babymother [125]3 years ago
6 0
\sqrt{0.3+ \sqrt{0.08} } =  \sqrt{a} + \sqrt{b} \\  \\  \sqrt{0.3+ \sqrt{0.08} }  \\ =  \sqrt{0.3+ \sqrt{4\times0,02} }  \\ = \sqrt{0.3 +2 \sqrt{0.02} } \\  \\  (a+b)^2=a^2+b^2+2ab\\   \\ \sqrt{ (\sqrt{a} + \sqrt{b})^2}  = \sqrt{a+b+2 \sqrt{ab} }\\   \sqrt{0.3+ \sqrt{0.08} } =  \sqrt{a} + \sqrt{b}  \\ \sqrt{0.3 +2 \sqrt{0.02} }=\sqrt{a+b+2 \sqrt{ab} } \\ 0.3+2\sqrt{0.02}=(a+b)+2 \sqrt{ab} \\
(a+b)=0.3 \\ ab=0.02 \\  \\  \\  \frac{1}{a} + \frac{1}{b}  = \frac{a+b}{ab}  \\  \\  \frac{a+b}{ab} =\frac{0.3}{0.02}   \\\frac{0.3}{0.02}=15 \\ \\  \frac{1}{a} + \frac{1}{b}=15


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Step-by-step explanation:

f(-1):  replace x in f(x) = x² + 3 with -1:  f(-1)  =  (-1)² + 3 = 4

f(-4) + g(-1) = (-4)² + 3 + <em>2(-1) + 3</em>  =  16 + 3 <em>- 2 + 3</em> = 20   <em>(since g(x) = 2X + 3)</em>

<em />

3f(x) - 2g(x) = 3[x² +3] - 2[2x + 3} = 3x² + 9 - 4x - 6  =  3x² - 4x + 3

f(g(2)):  First, evaluate g(2).  It is g(2) = 2(2) + 3 = 7.  Next, use this output, 7, as the input to f(x):    f(g(x)) = (7)² + 3 = 49 + 3 = 52

g(f(2)):  First, evaluate f(x) at x = 2:  f(2) = (2)² + 3 = 7.  Next, use this 7 as the input to g(x):     g(f(2)) = g(7) = 2(7) + 3 = 17

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Answer:

2x^2 = 6x - 5.

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