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AlladinOne [14]
2 years ago
5

Write the system of linear equations shown by the graph. Use slope-intercept form.

Mathematics
1 answer:
Andre45 [30]2 years ago
3 0

The required system of linear equations is y = -4x + 1 and y = 5x - 8.

Given that,
From the graph,
system of linear equation is to be determined.

Here,
The slope-intercept form of linear equation.
y = mx + c   - - - - - (1)


Equation of line 1
Since point (-1, 5), (0, 1) lies on the line 1.
The slope of line 1,
m = 1-5 / 0+1
m = -4
Now put this slope and 1 point in the equation.
5 = -4(-1) + c
c = 5 - 4
c = 1
now, put m and c in equation 1
y = - 4x + 1

Similarly, the equation of line 2 is given as y = 5x - 8.

Thus, the required system of linear equations is y = -4x + 1 and y = 5x - 8.

Learn more about lines here:

brainly.com/question/2696693

#SPJ1






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Step-by-step explanation:

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CaHeK987 [17]

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7 0
2 years ago
Hey go to attachments and help me out- thanks very much! this is my last question for today so it would really help also stay sa
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0.625 x 8 = 5 So just like last time, you know that 0.625g of butter is required to make 8 pancakes

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Hope this makes sense !

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Which answer is equivalent to 4 1/3*4 1/6?<br> a. 16<br> b .6√​16<br> c. 2<br> d. 3√​4
Talja [164]

Answer:

<h2>c. 2</h2>

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4^\frac{1}{3}\cdot4^\frac{1}{6}\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=4^{\frac{1}{3}+\frac{1}{6}}=4^{\frac{1\cdot2}{3\cdot2}+\frac{1}{6}}=4^{\frac{2}{6}+\frac{1}{6}}=4^\frac{2+1}{6}=4^\frac{3}{6}=4^\frac{3:3}{6:3}=4^{\frac{1}{2}}\\\\\text{use}\ a^\frac{m}{n}=\sqrt[n]{a^m}\\\\=\sqrt[2]{4^1}=\sqrt4=2

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