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solniwko [45]
2 years ago
11

The perimeter of a rectangle is 250 inches. if the length is 4 times as big as the width, what is the length and width of the re

ctangle?
Mathematics
1 answer:
yarga [219]2 years ago
8 0

The length and width of the rectangle are 7.90 inches and 31.6 inches respectively

It is given that,

Let the length of the rectangle = l

Let the width of the rectangle = w

The perimeter of the rectangle = 250 inches

l x w = 250 ....eq 1

Then,

Length is 4 times as big as width

4l = w

We need to find, the length and width of the rectangle

Putting the value of w in eqn 1

We get,

4l^{2} = 250

l^{2} = 62.5

l = \sqrt{62.5}

l = 7.90

Similarly, we can get,

w = 4l

w = 4 x 7.90

w = 31.6

Hence, the length and width of the rectangle are 7.90 inches and 31.6 inches respectively

To learn more about, perimeter, here

brainly.com/question/18793958

#SPJ4

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Please help it’s urgent multiple choice
Sergeeva-Olga [200]

Answer:

Theta = 52.1

Step-by-step explanation:

sin theta = opp / hyp

sin theta = 15/19

Take the inverse sin of each side

sin^-1 sin theta = sin^1- (15/19)

theta =52.13635364

To the nearest tenth

Theta = 52.1

7 0
3 years ago
Three numbers add up to 210. The second number is 10 more than the first and the third number is 3 times the first. Find the num
svp [43]

Answer:

I. First number, a = 40.

II. Second number, b = 50.

III. Third number, c = 120.

Step-by-step explanation:

Let the three numbers be a, b and c respectively.

Given the following data;

Translating the word problem into an algebraic equation, we have;

a + b + c = 210

b = a + 10

c = 3a

Substituting the value of b and c into the equation, we have;

a + a + 10 + 3a = 210

5a + 10 = 210

5a = 210 - 10

5a = 200

a = 200/5

<em>a = 40</em>

To find the value of b;

b = a + 10

b = 40 + 10

<em>b = 50</em>

To find c

c = 3a

c = 3*40

<em>c = 120</em>

5 0
3 years ago
Given the function g(x) = 4(3)x, Section A is from x = 1 to x = 2 and Section B is from x = 3 to x = 4.
Rudik [331]
The question is defective, or at least is trying to lead you down the primrose path.
The function is linear, so the rate of change is the same no matter what interval (section) of it you're looking at.
The "rate of change" is just the slope of the function in the section.  That's
         (change in f(x) ) / (change in 'x') between the ends of the section.
In Section A:Length of the section = (1 - 0) = 1f(1) = 5f(0) = 0change in the value of the function = (5 - 0) = 5Rate of change =            (change in the value of the function) / (size of the section) = 5/1  =  5
In Section B:Length of the section = (3 - 2) = 1 f(3) = 15f(2) = 10change in the value of the function = (15 - 10) = 5Rate of change =           (change in the value of the function) / (size of the section) = 5/1  =  5
Part A:The average rate of change of each section is 5.
Part B:The average rate of change of Section B is equal to the average rate of change of Section A.
Explanation:The average rates of change in every section are equalbecause the function is linear, its graph is a straight line,and the rate of change is just the slope of the graph.

4 0
3 years ago
Can someone please help me with these questions?
Dmitrij [34]

Expanded form is writing out everything and no simplifying.

A. c times c

B. t times t times t times t  

C. 2 times x times x times x  

D. 4 times 4 times h times h

E. 2 times 2 times 2 times l times l times l

F. a times a times a + 7 times b times b

Hope this helps :)

8 0
3 years ago
Can somebody help me with this. 35 points! :)))))
Vanyuwa [196]
HAIIII!!!! Your best option is C which shows 40 degrees!! I wish you best of luck
6 0
3 years ago
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