The set of all possible events Ω
Ω = 24 ( 4*7 = 28 stick)
<span>set of events favorable A
A = 7 ( </span><span>sticks of green is 7)
</span><span>Probability P
P(A) = A/</span>Ω = 7/28 = 1/4 = 0,25
Answer A
<span>The first person has the ability to draw seven green sticks of twenty-four </span>
False — if it doesn’t cross, it has no real roots.
There are two -main- approaches to answer this problem. By using the sine identity, or applying law of sines.
We'll do the sine trig. identity, as it is the most effective.
Given an angle '

' in a right triangle, '

' is defined as the opposite side of the triangle to the given angle, over the triangle's hypotenuse.
So, for this setup:

Now, we solve for x:
So, answer is 3.4
It's difficult to draw a tree diagram with this software.
Try to do it yourself & you will find the followings:
If A is selected (P(A) =1/2) we can get ether red (p(A & red)=4/7
so P(A∩red)= 1/2 x 4/7 = 4/14
Also we can get P(blue) = 3/7 & P(A∩blue) = 1/2 x 3/7 = 3/14
Same reasoning for B & you will get P(B∩read) 1/2 x 3/4 = 3/8
Also we can get P(B∩blue) = 1/2 x 1/4 = 1/8
Probability of blues is either 3/14 or 1/8
P(blue) = 3/8 +1/8 =19/56 = 0.339