<h3>
Answer: y = x+1</h3>
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Explanation:
f(x) = x^3 - 2x + 3
f ' (x) = 3x^2 - 2 ..... apply the power rule
f ' (1) = 3(1)^2 - 2 ... plug in x coordinate of given point
f ' (1) = 1
If x = 1 is plugged into the derivative function, then we get the output 1. This means the slope of the tangent line at (1,2) is m = 1. It's just a coincidence that the x input value is the same as the slope m value.
Now apply point slope form to find the equation of the tangent line
y - y1 = m(x - x1)
y - 2 = 1(x - 1)
y - 2 = x - 1
y = x - 1 + 2
y = x + 1 is the equation of the tangent line.
The graph is shown below. I used GeoGebra to make the graph.
Answer:
Cos θ = √7/3
Step-by-step explanation:
From the question given above, the following data were obtained:
Sine θ = √2 / 3
Cos θ =?
Recall
Sine θ = Opposite / Hypothenus
Sine θ = √2 / 3
Thus,
Opposite = √2
Hypothenus = 3
Next, we shall determine the Adjacent. This can be obtained as follow:
Opposite = √2
Hypothenus = 3
Adjacent =?
Hypo² = Adj² + Opp²
3² = Adj² + (√2)²
9 = Adj² + 2
Collect like terms
9 – 2 = Adj²
7 = Adj²
Take the square root of both side
Adjacent = √7
Finally, we shall determine the value Cos θ. This can be obtained as follow:
Adjacent = √7
Hypothenus = 3
Cos θ =?
Cos θ = Adjacent / Hypothenus
Cos θ = √7/3
We are given with an isosceles triangle having a vertex on the curve given y =<span>27-x^2</span> .
The area of the triangle, A= xy = x (27-x^2)
A' = 27-x^2-2x^2 = 0
x = 3
Amax = 3(27-9) = 54 units2
7) A. A variable is an unknown value, and x is unknown. Constants are known values so they cannot have X in it.
8)A again for the same reason as number 7
