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slamgirl [31]
1 year ago
13

It is given that AB is parallel to CD and points E, G, H, and F are collinear. The measure of ZEGF is 180°, by the definition of

a straight angle. ZAGE and ZAGF are
adjacent, so the measure of ZAGE plus the measure of ZAGF equals the measure of EGF, by the Angle Addition Postulate. Then, substituting for the measure of ZEGF
it can be said that the measure of ZAGE plus the measure of ZAGF equals 180°. so the measure of ZCHE plus the measure of ZAGF equals 180°.
Substituting once again means that the measure of ZAGE plus the measure of ZAGF equals the measure of ZCHE plus the measure of ZAGF. The measure of ZAGE
is equal to the measure of ZCHE
Finally, by the definition of congruence, ZAGE is congruent to ZCHE.
OZCHE and ZAGF are alternate interior angles; using the Addition Property of Equality
OZCHE and ZAGF are alternate interior angles; using the Subtraction Property of Equality
OZCHE and ZAGF are same-side interior angles; using the Subtraction Property of Equality
ZCHE and ZAGF are same-side interior angles; using the Addition Property of Equality

Mathematics
1 answer:
alex41 [277]1 year ago
3 0

The completed statement filled in with the correct option is presented as follows;

It is given that AB is parallel to CD and points, E, G, H, and F are collinear. The measure of ‹EGF is 180° by the definition of a straight angle. ‹AGE and ‹AGF are adjacent, so the measure of ‹AGE plus the measure of ‹AGF equals the measure of angle ‹EGF. It can be said that the measure of ‹AGE plus the measure of ‹AGF equals 180°. <u>‹CHE and ‹AG</u><u>F</u><u> are same side interior angles</u>, so the measure of angle ‹CHE plus the measure of angle ‹AGF equals 180°.

Substituting once again means that the measure of ‹AGE plus the measure of angle ‹AGF equals the measure of angle ‹CHE plus the measure of ‹AGF. The measure of angle ‹AGE is equal to the measure of ‹CHE <u>u</u><u>sing the </u><u>Subtraction</u><u> </u><u>P</u><u>roperty of </u><u>E</u><u>quality</u>. Finally, by the definition of congruency, ‹AGE is congruent to ‹CHE

The correct option is therefore;

  • ‹CHE and ‹AGE are same side interior angles; using the Subtraction Property of Equality

<h3>What relationships between angles formed by parallel lines can be used to complete the paragraph?</h3>

Angles, ‹CHE and ‹AGF are angles formed on the same side of the common transversal, EF, and are formed on the interior part of AB and CD.

Given that ‹CHE and ‹AGF are both on the line FGHE, and together with ‹CHF and ‹AGE form two linear pair angles, ‹CHE and ‹AGF are supplementary angles and add up to 180°.

According to the substitution property of equality, both sides of an equation remain equal following the subtraction of the same quantity from both sides.

Given that we have:

‹AGE + ‹AGF = ‹CHE + ‹AGF

Subtracting ‹AGF from both sides gives;

‹AGE = ‹CHE (subtraction property of equality)

Learn more about the angles formed by parallel lines here:

brainly.com/question/17430387

#SPJ1

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Express 6 3/4 in simplest radical form
Hoochie [10]

Answer:

4√6^3

Step-by-step explanation:

3 0
3 years ago
Help... I need this done by 12:30
alex41 [277]
Do you still need a answer ???
5 0
3 years ago
Given the force field F, find the work required to move an object on the given oriented curve. F = (y, - x) on the path consisti
timofeeve [1]

Answer:

0

Step-by-step explanation:

We want to compute the curve integral (or line integral)

\bf \int_{C}F

where the force field F is defined by

F(x,y) = (y, -x)

and C is the path consisting of the line segment from (1, 5) to (0, 0) followed by the line segment from (0, 0) to (0, 9).

We can write  

C = \bf C_1+C_2

where  

\bf C_1 =  line segment from (1, 5) to (0, 0)  

\bf C_2 = line segment from (0, 0) to (0, 9)

so,

\bf \int_{C}F=\int_{C_1}F+\int_{C_2}F

Given 2 points P, Q in the plane, we can parameterize the line segment joining P and Q with

<em>r(t) = tQ + (1-t)P for 0 ≤ t ≤ 1 </em>

Hence \bf C_1 can be parameterized as

\bf r_1(t) = (1-t, 5-5t) for 0 ≤ t ≤ 1

and \bf C_2 can be parameterized as

\bf r_2(t) = (0, 9t) for 0 ≤ t ≤ 1

The derivatives are

\bf r_1'(t) = (-1, -5)

\bf r_2'(t) = (0, 9)

and

\bf \int_{C_1}F=\int_{0}^{1}F(r_1(t))\circ r_1'(t)dt=\int_{0}^{1}(5-5t,t-1)\circ (-1,-5)dt=0

\bf \int_{C_2}F=\int_{0}^{1}F(r_2(t))\circ r_2'(t)dt=\int_{0}^{1}(9t,0)\circ (0,-9)dt=0

In consequence,

\bf \int_{C}F=0

6 0
4 years ago
a zoo is building a new giraffe exhibit and needs to fence an outdoor triangular​ area, with the barn forming one side of the tr
konstantin123 [22]

Answer:

Yes, the zoo needs to order more fencing. The zoo has 54 ft of fence remaining for the unknown side.

If the unknown side is assumed to have this length, sin (θ) = 1.2857. which is not possible, so the triangle cannot be formed.

Step-by-step explanation:

Let a be the length of the third side of the triangle.

a = 127 - 73 = 54 ft

Let the angle that a makes with the barn be θ

The diagram of this question is attached to this solution.

Using the sine rule, we can examine if the remaining fencing material would be enough by checking if (sin θ) is realistic.

Using sine rule,

[a/(sin 72°)] = [73/(sin θ)]

[54/sin 72°] = [73/sin θ]

sin θ = (73 × sin 72°)/54 = 1.2857

sin θ = 1.2857

This is obviously not a realistic value for sin θ since it is known that sin θ ranges between 0 and 1.

The 54 ft is obviously not enough.

Hence, the zoo needs more fencing material to be able to complete the outdoor triangular giraffe exhibit.

Hope this Helps!!!

5 0
3 years ago
Someone helpppppppp pleaseeeeeee
laila [671]

So here is one thing that might help. Look at both the 1st and 3rd triangles, they have a right angle, just like the one you are trying to figure out. The centemeters is 4 for the longest side and the decimal, 0.57, is going to be multiplied 4 times. The decimal would be 2.28 when multiplied, and the angle is the same as the two triangles I spoke at the second sentence. x is equal to 2.28 but we need to change it to 1 decimal place, meaning that it is 2.3.

Hope this helped!

Nate

6 0
4 years ago
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