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Mariulka [41]
3 years ago
9

Which is true about the line whose equation is y+3=0

Mathematics
2 answers:
astraxan [27]3 years ago
8 0
Y+3=0 is vertical line -3 on the graph. 

Hope this helps there was no choices. 
bonufazy [111]3 years ago
4 0
Vertical line on graph -3
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Expand logarithms equation
Bess [88]

Answer:

log_2(x) + log_2(y) + log_2(z)

Step-by-step explanation:

5log_2(xyz)^{1/5}\\\\5log_2(x)^{1/5} + 5log_2(y)^{1/5} + 5log_2(z)^{1/5}\\\\log_2(x) + log_2(y) + log_2(z)

4 0
3 years ago
The Yert family hires a landscaping company for 30 weeks. There are two companies to choose from. Green Lawns charges $1 for the
Nikolay [14]

Answer:

$133.77

I am pretty sure that this is the answer.

Step-by-step explanation:

1 + (1.25)^29 = 646.23

200 + (20 x 29) = 780

780 - 646.23 = 133.77

Tell me if I am wrong.

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6 0
3 years ago
bernite is selling candy bars for a school fundraiser. the school paid $20 for a box of 15 king size candy bars and bernite sell
NikAS [45]
The school originally used $20 for the purchase of the candy.
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Sub in the 15 bars for t
Y=2(15)
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Therefore the school made $10, because they earned an extra $10 in comparison to the amount they bought the candy bars for, which was $20.
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6 0
3 years ago
98464 rounded to the nearest ten thousand?​
dusya [7]

Answer:

100000

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Let P be the parabola with focus (0,4) and directrix y=x.Write an equation whose graph is a parabola with a vertical directrix t
prisoha [69]

Answer:

y²=4√2.x

Step-by-step explanation:

The focus is at (0,4) and directrix is y=x or x-y =0, for a parabola P.

The distance between the focus and the directrix of the parabola P is

\frac{ |0-4| }{\sqrt{(1)^{2}+(-1)^{2}  } }=\frac{4}{\sqrt{2} }

{Since the perpendicular distance of a point (x1, y1) from the straight line ax+by+c =0 is given by \frac{ |ax1+by1+c| }{\sqrt{a^{2}+b^{2}  } } }

Let us assume that the equation of the parabola which is congruent with parabola P is y²=4ax

{Since the parabola has vertical directrix}

Hence, the distance between focus and the directrix is 2a = \frac{4}{\sqrt{2} }, {Two parabolas are congruent when the distances between their focus and the directrix are same}

⇒ a=√2

Therefore, the equation of the parabola is y²=4√2.x (Answer)

3 0
3 years ago
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