Answer:
Explanation:
The accounting equation is presented below:
Particulars Assets = Liabilities = Stockholders equity
Cash Supplies Account payable Retained earnings
1. Service
Performed $20,000 $20,000
2. Supplies
Purchased $4,000 $4,000
3. Supplies
Used -$3,000 -$3,000
Total $20,000 $1,000 $4,000 $17,000
Answer:
$7,200
Explanation:
According to the scenario, computation of the given data are as follows,
Total cost = $84,000
Salvage value = $12,000
Estimated life = 10 years
So, we can calculate depreciation expense by using following formula,
Depreciation yearly = (Total cost - Salvage value) ÷ Estimated life
= ($84,000 - $12,000) ÷ 10
= $72,000 ÷ 10
= $7,200
Answer:
The correct answer is A.true.
Explanation:
Fixed asset accounting systems include cost allocation and matching procedures that are not part of routine expenditure systems.
As per financial accounting standards fixed assets cost is capitalized and than depreciated over its useful life. Only that amount of asset cost is charged in profit and loss account that has been depreciated during the reporting period. However, in case of other routine expenses full amount is charged in p/l, in the period, in which these costs are incurred.
First, you have to calculate the amount of tuition when the student reaches age 18. Do this by multiplying $11,000 by 1.07 each year from age 12 until it reaches age 18. Thus, 7 times.
At age 18: 16,508
At age 19: 17,664
At age 20: 18,900
At age 21: 20,223
Then, we use this formula:
A = F { i/{[(1+i)^n] - 1}}
where A is the monthly deposit each year, F is the half amount of the tuition each year illustrated in the first part of this solution, n is the number of years lapsed.
At age 18:
A = (16508/2) { 0.04/{[(1+0.04)^6] - 1}} = $1,244.389 deposit for the 1st year
Ate age 19
A = (17664/2) { 0.04/{[(1+0.04)^7] = $1,118 deposit for the 2nd year
At age 20:
A = (18900/2) { 0.04/{[(1+0.04)^8] = $1,025 deposit for the 3rd year
At age 21:
A = (18900/2) { 0.04/{[(1+0.04)^8] = $955 deposit for the 4th year
