Answer:
C = 80
Step-by-step explanation:
A cyclic quadrilateral is one where all 4 vertices touch the circumference of a circle.
It has 1 interesting property that should concern you: <B + <D = 180 degrees.
3x - 59 + 2x - 1 = 180 Combine like terms
5x - 60 = 180 Add 60 to both sides.
5x = 180 + 60
5x = 240
x = 240/5
x = 48
Now go to 2x + 4.
x = 48
A = 2*48 + 4
A = 96 + 4
A = 100
So C = 180 - 100
C = 80
The length of the daylight was 9 hr 10 min
We are given : Zeros x=7 and x=4 and leading coefficent 1.
In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.
For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).
So, we need to multiply (x-7) and (x-4) by foil method.
We get
(x-7)(x-4) = x*x + x* -4 -7*x -7*-4
x^2 -4x -7x +28.
Combining like terms, we get
-4x-7x = -11x
x^2 -4x -7x +28 = x^2 -11x +28.
Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.
We get
1(x^2 -11x +28) = x^2 -11x +28.
Therefore, the required quadratic function in standard form is x^2 -11x +28.
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Answer:
3. vertical stretch by a factor of 2; shift right 1 and down 1
4. shift left 4 and up 4 (no stretch or shrink)
Step-by-step explanation:
The vertex form equation is ...
y = a(x -h)^2 +k
It represents a vertical stretch of the parent function by a factor of 'a', a right shift of 'h', and an upward shift of 'k'.
Compare the the given equations to the above form to see the transformations.
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3. (a, h, k) = (2, 1, -1) ⇒ vertical stretch by a factor of 2; shift right 1, down 1
4. (a, h, k) = (1, -4, 4) ⇒ no vertical stretch; shift left 4, up 4
I feel like it’s 180 dregrees, good luck!
