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Nat2105 [25]
2 years ago
11

An experiment consists of tossing 4 unbiased coins simultaneously. What is the number of simple events in this experiment?

Mathematics
1 answer:
kupik [55]2 years ago
5 0

The number of simple events in this experiment according to the probability is 16.

According to the statement

we have to find that the number of simple events in this experiment.

So, For this purpose, we know that the

Simple events are the events where one experiment happens at a time and it will be having a single outcome. The probability of simple events is denoted by P(E) where E is the event.

And according to the given information is:

Total number of coins tossed is 4.

then

the simple events become

Simple events = no. of coins * total coins tossed

Simple events = 4*4

Now solve it then

Simple events = 16.

So, The number of simple events in this experiment according to the probability is 16.

Learn more about simple events here

brainly.com/question/7965468

#SPJ4

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State the X- and Y- intercepts of each function. <br><br> -1/2x + 3y = -3
Dafna1 [17]
For the equation -1/2x+3y=-3
 the x-intercept=6
 the y-intercept=-1
7 0
3 years ago
The perimeter of Stephanie’s triangle is half the perimeter of Juan’s triangle. Juan’s triangle is shown. Write a numerical expr
denpristay [2]

The perimeter of a triangle is the sum of all side lengths of the triangle. The numerical expression for the perimeter of Stephanie's triangle is: \frac 12 \times 25

Let the sides of Juan's triangle be x, y and z. So:

x = 5 \\ y = 8\\ z = 12

The perimeter (J) of Juan's triangle is calculated by adding all sides.

So:

J =x +y +z

This gives:

J =5 + 8 + 12

J =25

From the question, we understand that:

The perimeter (S) of Stephanie's triangle is half that of Juan.

This means that:

S = \frac 12J

Substitute 25 for J

S = \frac 12 \times 25

Hence, the numerical expression for the perimeter of Stephanie's triangle is: \frac 12 \times 25

Read more about perimeters at:

brainly.com/question/11957651

4 0
3 years ago
Read 2 more answers
A math professor notices that scores from a recent exam are normally distributed with a mean of 61 and a standard deviation of 8
Alexeev081 [22]

Answer:

a) 25% of the students exam scores fall below 55.6.

b) The minimum score for an A is 84.68.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 61 and a standard deviation of 8.

This means that \mu = 61, \sigma = 8

(a) What score do 25% of the students exam scores fall below?

Below the 25th percentile, which is X when Z has a p-value of 0.25, that is, X when Z = -0.675.

Z = \frac{X - \mu}{\sigma}

-0.675 = \frac{X - 61}{8}

X - 61 = -0.675*8

X = 55.6

25% of the students exam scores fall below 55.6.

(b) Suppose the professor decides to grade on a curve. If the professor wants 0.15% of the students to get an A, what is the minimum score for an A?

This is the 100 - 0.15 = 99.85th percentile, which is X when Z has a p-value of 0.9985. So X when Z = 2.96.

Z = \frac{X - \mu}{\sigma}

2.96 = \frac{X - 61}{8}

X - 61 = 2.96*8

X = 84.68

The minimum score for an A is 84.68.

8 0
3 years ago
15. Xavier filled a 36 ounce cup with water. He
aniked [119]

Answer:28.8 ounces

Step-by-step explanation:20% -36 =22.8

4 0
3 years ago
The half-life of a certain radioactive material is 83 hours. An initial amount of the material has a mass of 67 kg. Write an exp
Anvisha [2.4K]

Answer:

  • Initial amount of the material is 67 kg
  • Hal-life is 83 hours

<u>The required equation is:</u>

  • m(x) = 67 * (1/2)^{x/83}, where m- remaining amount of the radioactive material, x - number of hours

<u>After 5 hours the material remains:</u>

  • m(5) = 67 * (1/2)^{5/83} = 64.260 (rounded)
4 0
3 years ago
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