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3 years ago

Tell me 3 points that would be on the graph of y = 2x + 3

Mathematics

2 answers:

Rainbow [258]3 years ago

6 0

Answer:

-1.5,0, 0,3 and -4,-5

Step-by-step explanation:

krek1111 [17]3 years ago

5 0

That is form of y= mx+b so you have one point is (0,3) and other can be this (1,5) (2,7)

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Is perpendicular to OS. is a_____line.

Step2247 [10]

I would answer the problem but first upload the diagram

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3 years ago

Explain what needs to be fixed. 2n + 10 = -2 2n = 12 Step one n = 6 Step two

Brilliant_brown [7]

Answer:

step one needs to be fixed... you are supposed to subtract 10 from both sides of the equation.

Step-by-step explanation:

STEP 1: Move all terms not containing n to the right side of the equation.

$2n=-12$

STEP 2: Divide each term by 2 and simplify.

$n=-6$

8 0

3 years ago

The asymptote of the functio f (x) =3^x +4 is y

Y_Kistochka [10]

Since that f is continuous for all x in R, and f > 0 then

$\lim\limits_{x\to -\infty}3^x+4=4$

for hence the asymptote is y = 4

5 0

3 years ago

Read 2 more answers

A blood bank needs 8 people to help with a blood drive. 11 people have volunteered.

11111nata11111 [884]

Answer:

165

Step-by-step explanation:

formula is

nCr = n!/(r!(n−r)!)

r= 8 = number of choosing objects from the set

n = 11 = total number of objects in the set

C(n,r)=C(11,8)

=11!/(8!(11−8)!)

! means factorial

factorial means to multiply by decreasing positive numbers.

For example, 8! = 8 ∗ 7 ∗ 6 ∗ 5 ∗ 4 ∗ 3 ∗ 2 ∗ 1 = 40320

=11!/8!×3!

= 165

massedu

5 0

2 years ago

Read 2 more answers

A line passes through (2,-1) and (4,5). What answer is the equation of the line? -3x+5y=-13

Sliva [168]

The equation of the line passes through (2, -1) and (4, 5) is -3x + y = - 7 So, option 2 is correct.

Solution:

Given, two points are (2, -1) and (4, 5)

We have to find that a line that passes through the given two points.

First let us find the slope of the line that passes through given two points.

So, slope of line "m" is given as:

$\mathrm{m}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$\text { where, }\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right) \text { are two points on line. }$

So slope of our line = $\frac{5-(-1)}{4-2}=\frac{5+1}{2}=3$

Now, let us find the line equation using point slope form:

$y-y_{1}=m\left(x-x_{1}\right) \text { where } m \text { is slope and }\left(x_{1}, y_{1}\right) \text { is point on the line. }$

Then equation of line is,

y – 5 = 3(x – 4)

y – 5 = 3x – 12

-3x + y = 5 – 12

-3x + y = -7

Hence, the line equation is -3x + y = - 7 so, option 2 is correct.

4 0

3 years ago