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2 years ago

Please do it for me Im struggling a lot right now with math

Mathematics

1 answer:

Basile [38]2 years ago

8 0

Answer: wait what is the question asking i can’t really see

Step-by-step explanation:

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Is x^4 +400 a complex conjugate

nadya68 [22]

3 0

3 years ago

Solve this x²+8/10 -x = 10/2

AysviL [449]

$x^2+\frac{8}{10}-x=\frac{10}{2}\\
x^2-x+\frac{8}{10}-\frac{10}{2}=0\\
x^2-x+\frac{8}{10}-\frac{50}{10}=0\\
x^2-x-\frac{42}{10}=0\\
x^2-x+\frac{1}{4}-\frac{1}{4}-\frac{42}{10}=0\\
(x-\frac{1}{2})^2=\frac{1}{4}+\frac{42}{10}\\
(x-\frac{1}{2})^2=\frac{5}{20}+\frac{84}{20}\\
(x-\frac{1}{2})^2=\frac{89}{20}\\
x-\frac{1}{2}=\sqrt{\frac{89}{20}} \vee x-\frac{1}{2}=-\sqrt{\frac{89}{20}}\\
x=\frac{1}{2}+\frac{\sqrt{89}}{\sqrt{20}} \vee x=\frac{1}{2}-\frac{\sqrt{89}}{\sqrt{20}}\\


$
$x=\frac{1}{2}+\frac{\sqrt{89}}{2\sqrt{5}} \vee x=\frac{1}{2}-\frac{\sqrt{89}}{2\sqrt5}}\\
x=\frac{1}{2}+\frac{\sqrt{445}}{10} \vee x=\frac{1}{2}-\frac{\sqrt{445}}{10}}\\
x=\frac{5+\sqrt{445}}{10} \vee x=\frac{5-\sqrt{445}}{10}}\\$

7 0

3 years ago

Under her cell phone plan, Peyton pays a flat cost of $48 per month and $3 per gigabyte. She wants to keep her bill at $60.60 pe

Ad libitum [116K]

Answer: 4.20 gigabyte

Step-by-step explanation:

Based on the information given in the question, the equation that can be used to determine the the number of gigabytes of data Peyton can use while staying within her budget will be:

48 + 3g = 60.60

3g = 60.60 - 48

3g = 12.60

g = 12.60/3

= 4.20

The number of gigabytes of data is 4.20g

4 0

3 years ago

Read 2 more answers

If tn = 4n+1, find t1, t2, t3, and tn+1. Express tn+1−tn in its simplest form.

Doss [256]

Answer:

$t_1=5$

$t_2=9$

$t_3=13$

$t_{n+1}-t_n=4$

Step-by-step explanation:

We have that:

$t_n=4n+1$

When we substitute n=1, we get:

$t_1=4*1+1=5$

When we substitute n=2 we get:

$t_2=4*2+1=9$

When we substitute n=3, we get:

$t_3=4*3+1=13$

When we substitute n=n+1, we get:

$t_{n+1}=4*(n+1)+1=4n+5$

Now

$t_{n+1}-t_n=4n+5-(4n+1)$

We expand and simplify to obtain:

$t_{n+1}-t_n=4n+5-4n-1$

$t_{n+1}-t_n=4$

3 0

3 years ago

Plese i need help on this one !!!!!!!

patriot [66]

Answer:

I got 32.

Step-by-step explanation:

I used the Pythagorean theorem to find the lengths of the width and length. The length between (-1, 4) and (3, 3) was approximately 4 in. The distance between (-1, 4) and (-3, -4) was approximately 8 in. I then used those numbers to find the perimeter ((2*4)+(2*8))

8 0

3 years ago

Read 3 more answers