<img src="https://tex.z-dn.net/?f=16y%20%5E%7B5%7D%20-%2012y%20%5E%7B4%7D%20%2B%204y%20%5C%5C%20%5C%5C%2064%20a%20%5Ctimes%20%5E

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1 year ago

%7B2%7D%20-%2049ay%20%5E%7B2%7D%20" id="TexFormula1" title="16y ^{5} - 12y ^{4} + 4y \\ \\ 64 a \times ^{2} - 49ay ^{2} " alt="16y ^{5} - 12y ^{4} + 4y \\ \\ 64 a \times ^{2} - 49ay ^{2} " align="absmiddle" class="latex-formula">
Plss answer this

Mathematics

1 answer:

Shkiper50 [21]1 year ago

7 0

Answer:

see explanation

Step-by-step explanation:

Assuming you require to factorise the expressions

16 $y^{5}$ - 12 $y^{4}$ + 4y ← factor out 4y from each term

= 4y(4 $y^{4}$ - 3y³ + 1)

--------------------------------

64ax² - 49ay² ← factor out a from each term

= a(64x² - 49y²) ← this is a difference of squares and factors in general as

a² - b² = (a - b)(a + b) , then

64x² - 49y²

= (8x)² - (7y)²

= (8x - 7y)(8x + 7y)

then

64ax² - 49ay² = a(8x - 7y)(8x + 7y)

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