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Sindrei [870]
1 year ago
6

%7B2%7D%20-%2049ay%20%5E%7B2%7D%20" id="TexFormula1" title="16y ^{5} - 12y ^{4} + 4y \\ \\ 64 a \times ^{2} - 49ay ^{2} " alt="16y ^{5} - 12y ^{4} + 4y \\ \\ 64 a \times ^{2} - 49ay ^{2} " align="absmiddle" class="latex-formula">
Plss answer this
​
Mathematics
1 answer:
Shkiper50 [21]1 year ago
7 0

Answer:

see explanation

Step-by-step explanation:

Assuming you require to factorise the expressions

16y^{5} - 12y^{4} + 4y ← factor out 4y from each term

= 4y(4y^{4} - 3y³ + 1)

--------------------------------

64ax² - 49ay² ← factor out a from each term

= a(64x² - 49y²) ← this is a difference of squares and factors in general as

a² - b² = (a - b)(a + b) , then

64x² - 49y²

= (8x)² - (7y)²

= (8x - 7y)(8x + 7y)

then

64ax² - 49ay² = a(8x - 7y)(8x + 7y)

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Answer:

Let's call:

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Step-by-step explanation:

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