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1 year ago

. Which graph has f(x) = 1xI as its parent function?

Mathematics

1 answer:

Blababa [14]1 year ago

6 0

Answer: Im not sure

Step-by-step explanation:

you didnt list/provide the graphs for me to answer. :I

You might be interested in

What is the value of M ?

Murrr4er [49]

Answer:

m = 124 degrees.

Step-by-step explanation:

The sum of the interior angles of a triangle is 180.

The angle opposite m + 56 + 68 = 180.

The angle opposite m = 56.

The angle opposite m + m = 180, so 56 + m = 180.

Angle m = 124.

6 0

2 years ago

a worker A finishes a project on his own in 12 days. the worker completes the same work alone in 16 days. the two workers starte

ankoles [38]

Answer:

Worker B needs 9 days to finish the rest of the work

Step-by-step explanation:

Proportions

Worker A finishes a project on his own in 12 days and worker B does the same in 16 days.

Worker A does 1/12 of the project in one day and worker B does 1/16 of the project in one day. When working together, they do

$\frac{1}{12}+\frac{1}{16}=\frac{7}{48}$

After 3 days they have completed:

$3*\frac{7}{48}=\frac{7}{16}$

parts of the project, this means it still remains:

$1-\frac{7}{16}=\frac{9}{16}$

parts of the project and it is done by B alone. Since B does $\frac{1}{16}$ per day, he now takes

$\displaystyle \frac{\frac{9}{16}}{\frac{1}{16}}=9$

days to complete the project.

Worker B needs 9 days to finish the rest of the work

4 0

2 years ago

Directions:Use the product rule to simplify the following monomials.

abruzzese [7]

7) Answer = $-24x^8y^{11}$

$\left(8x^4y^2\right)\left(-3x^4y^9\right)$

$=-8x^4y^2\cdot \:3x^4y^9$

$=-24x^4y^2x^4y^9$

$=-24x^8y^2y^9$

$=-24x^8y^{11}$

8) Answer = $-30y^6$

$2y\left(-5\right)y^2\cdot \:3y^3$

$=-30yy^2y^3$

$=-30y^{1+2+3}$

$=-30y^6$

9) Answer = $-6x^4y^5$

$\left(-2xy\right)\left(xy\right)\left(3x^2y^3\right)$

$=-2xyxy\cdot \:3x^2y^3$

$=-6xyxyx^2y^3$

$=-6x^4yyy^3$

$=-6x^4y^5$

3 0

2 years ago

For each of the following vector fields F , decide whether it is conservative or not by computing curl F . Type in a potential f

Phantasy [73]

The key idea is that, if a vector field is conservative, then it has curl 0. Equivalently, if the curl is not 0, then the field is not conservative. But if we find that the curl is 0, that on its own doesn't mean the field is conservative.

$\mathrm{curl}\vec F=\dfrac{\partial(5x+10y)}{\partial x}-\dfrac{\partial(-6x+5y)}{\partial y}=5-5=0$

We want to find $f$ such that $\nabla f=\vec F$ . This means

$\dfrac{\partial f}{\partial x}=-6x+5y\implies f(x,y)=-3x^2+5xy+g(y)$

$\dfrac{\partial f}{\partial y}=5x+10y=5x+\dfrac{\mathrm dg}{\mathrm dy}\implies\dfrac{\mathrm dg}{\mathrm dy}=10y\implies g(y)=5y^2+C$

$\implies\boxed{f(x,y)=-3x^2+5xy+5y^2+C}$

so $\vec F$ is conservative.

$\mathrm{curl}\vec F=\left(\dfrac{\partial(-2y)}{\partial z}-\dfrac{\partial(1)}{\partial y}\right)\vec\imath+\left(\dfrac{\partial(-3x)}{\partial z}-\dfrac{\partial(1)}{\partial z}\right)\vec\jmath+\left(\dfrac{\partial(-2y)}{\partial x}-\dfrac{\partial(-3x)}{\partial y}\right)\vec k=\vec0$

Then

$\dfrac{\partial f}{\partial x}=-3x\implies f(x,y,z)=-\dfrac32x^2+g(y,z)$

$\dfrac{\partial f}{\partial y}=-2y=\dfrac{\partial g}{\partial y}\implies g(y,z)=-y^2+h(y)$

$\dfrac{\partial f}{\partial z}=1=\dfrac{\mathrm dh}{\mathrm dz}\implies h(z)=z+C$

$\implies\boxed{f(x,y,z)=-\dfrac32x^2-y^2+z+C}$

so $\vec F$ is conservative.

$\mathrm{curl}\vec F=\dfrac{\partial(10y-3x\cos y)}{\partial x}-\dfrac{\partial(-\sin y)}{\partial y}=-3\cos y+\cos y=-2\cos y\neq0$

so $\vec F$ is not conservative.

$\mathrm{curl}\vec F=\left(\dfrac{\partial(5y^2)}{\partial z}-\dfrac{\partial(5z^2)}{\partial y}\right)\vec\imath+\left(\dfrac{\partial(-3x^2)}{\partial z}-\dfrac{\partial(5z^2)}{\partial x}\right)\vec\jmath+\left(\dfrac{\partial(5y^2)}{\partial x}-\dfrac{\partial(-3x^2)}{\partial y}\right)\vec k=\vec0$

Then

$\dfrac{\partial f}{\partial x}=-3x^2\implies f(x,y,z)=-x^3+g(y,z)$

$\dfrac{\partial f}{\partial y}=5y^2=\dfrac{\partial g}{\partial y}\implies g(y,z)=\dfrac53y^3+h(z)$

$\dfrac{\partial f}{\partial z}=5z^2=\dfrac{\mathrm dh}{\mathrm dz}\implies h(z)=\dfrac53z^3+C$

$\implies\boxed{f(x,y,z)=-x^3+\dfrac53y^3+\dfrac53z^3+C}$

so $\vec F$ is conservative.

4 0

3 years ago

7/8 = /48 A. 1 B. 6 C. 42 D. 13

Vsevolod [243]

7/8 = x/48

Cross multiply, which is: a/b = c/d ⇒ ad = bc

After cross multiplying, we get:

8x = 7(48)

8x = 336

Divide 8 on both sides

x = 42

Your final answer is B. 42.

6 0

3 years ago