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BARSIC [14]
1 year ago
9

If the surface area of the cone below is 628.32, find its volume. (Diameter is 16)

Mathematics
1 answer:
Brilliant_brown [7]1 year ago
3 0

To solve the question given

We will follow the steps below

First, the surface area is given to be 628.32

diameter = 16 this implies that radius = d/2 = 16/2 = 8

First, using the formula

surface area of a cone = πr² + πrl

we will find l

remember that π= 3.14

substituting the values into the above formula

surface area of a cone = πr² + πrl

628.32 = 3.14(8)² + 3.14(8)l

Next is to solve for l

628.32 = 200.96 +25.12 l

subtract 200.96 from both-side of the equation

628.32 - 200.96= 200.96 - 200.96 +25.12 l

427.36 = 25.12 l

Divide both-side of the equation by 25.12

427.36/25.12 = 25.12 l/25.12

17.01 = l

slant height (l) = 17.01

We can now calculate the volume of the cone using the formula:

V\text{ = }\frac{1}{3}\pi r^2\sqrt{l^2-r^2}

substituting r=8 π = 3.14 and l = 17.01 in the above formula

V=\frac{1}{3}\text{ }\times3.14\times(8)^2\text{ }\times\sqrt{(17.01)^2-(8)^2}

V=\text{ }\frac{1}{3\text{ }}\times3.14\times64\text{ }\times\sqrt{289.3401\text{ - 64}}

V=\text{ }\frac{1}{3}\times200.96\text{ }\times\sqrt{225.3401}

V\text{ =}\frac{1}{3}\times\text{ 200.96}\times15.01V\text{ = }\frac{3016.4096}{3}

V=1005.47

Volume of the cone is 1 005.47

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Step-by-step explanation:

Given that:

Volume of container = 98,000 cubic volume

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Among persons donating blood to a clinic, 85% have Rh+ blood (that is, the Rhesus factor is present in their blood.) Six people
Leona [35]

Answer:

a) There is a 62.29% probability that at least one of the five does not have the Rh factor.

b) There is a 22.36% probability that at most four of the six have Rh+ blood.

c) There need to be at least 8 people to have the probability of obtaining blood from at least six Rh+ donors over 0.95.

Step-by-step explanation:

For each person donating blood, there are only two possible outcomes. Either they have Rh+ blood, or they do not. This means that we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

p = 0.85, n = 6.

a) fine the probability that at least one of the five does not have the Rh factor.

Either all six have the factor, or at least one of them do not. The sum of the probabilities of these events is decimal 1. So:

P(X < 6) + P(X = 6) = 1

P(X < 6) = 1 - P(X = 6)

In which:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{6,6}.(0.85)^{6}.(0.15)^{0} = 0.3771

So

P(X < 6) = 1 - P(X = 6) = 1 - 0.3771 = 0.6229

There is a 62.29% probability that at least one of the five does not have the Rh factor.

b) find the probability that at most four of the six have Rh+ blood.

Either more than four have Rh+ blood, or at most four have. So

P(X \leq 4) + P(X > 4) = 1

P(X \leq 4) = 1 - P(X > 4)

In which

P(X > 4) = P(X = 5) + P(X = 6)

P(X = 5) = C_{6,5}.(0.85)^{5}.(0.15)^{1} = 0.3993

P(X = 6) = C_{6,6}.(0.85)^{6}.(0.15)^{0} = 0.3771

P(X > 4) = P(X = 5) + P(X = 6) = 0.3993 + 0.3771 = 0.7764

P(X \leq 4) = 1 - P(X > 4) = 1 - 0.7764 = 0.2236

There is a 22.36% probability that at most four of the six have Rh+ blood.

c) The clinic needs six Rh+ donors on a certain day. How many people must donate blood to have the probability of obtaining blood from at least six Rh+ donors over 0.95?

With 6 donors:

P(X = 6) = C_{6,6}.(0.85)^{6}.(0.15)^{0} = 0.3771

37.71% probability of obtaining blood from at least six Rh+ donors over 0.95.

With 7 donors:

P(X = 6) = C_{7,6}.(0.85)^{6}.(0.15)^{1} = 0.3960

0.3771 + 0.3960 = 0.7764 = 77.64% probability of obtaining blood from at least six Rh+ donors over 0.95.

With 8 donors

P(X = 6) = C_{8,6}.(0.85)^{6}.(0.15)^{2} = 0.2376

0.3771 + 0.3960 + 0.2376 = 1.01 = 101% probability of obtaining blood from at least six Rh+ donors over 0.95.

There need to be at least 8 people to have the probability of obtaining blood from at least six Rh+ donors over 0.95.

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