The polynomial is (mx^3+3)(2x²+5x+2)-(8x^5 +20x^4)
if it is reduced to 8x^3+6x²+15x+6, so we can find the value of m
(mx^3+3)(2x²+5x+2)-(8x^5+20x^4) = <span>8x^3+6x²+15x+6
</span>2mx^5+5mx^4+2mx^3+6x²+15x+6-8x^5-20x^4=<span>8x^3+6x²+15x+6
</span>2mx^5+5mx^4+2mx^3=8x^3+6x²+15x+6-6x²-15x-6+ <span>8x^5+20x^4
</span>= 8x^5+20x^4+<span>8x^3= 4(2x^5+5x^4+2x^3)
finally
</span>m(2x^5+5x^4+2x^3)=<span>4(2x^5+5x^4+2x^3), and after simplification
</span>
C: m=4
<span>4. When the expression is factored x²-3x-18 completely,
</span>
one of its factor is x-6
<span>x²-3x-18=0
</span>D= 9-4(-18)= 81, sqrtD=9 x=3-9/2= -6/2= -3, and x=3+9 / 2= 6
so <span>x²-3x-18= (x-6)(x+6)
</span>
Answer:
98
Step-by-step explanation:
option d..............
Answer:
(0,-3)
Step-by-step explanation:
You can just graph it and find the center.
Please put me as brainliest. Thank you.
This is a question that needs a bit of common sense to get to the actual answer that is desired. Firstly there is one information given .The other information has to be found from common sense. ! single handshake requires 2 people. Now we can easily determine the number of people doing 66 handshakes.
Then
The number of people required for 1 hand shake = 2
Then
The number of people required to do 66 handshakes = ( 2 * 66) people
= 132 people
Then it can be said that there were 132 people in the party. I hope the process of doing this problem is clear to you.
