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zysi [14]
2 years ago
7

How to write 103,727,495

Mathematics
1 answer:
zysi [14]2 years ago
3 0

Answer:

One hundred three million seven hundred twenty-seven thousand four hundred and ninety-five

Step-by-step explanation:

103,000,000 = One hundred three million

103,727,000 = One hundred three million seven hundred twenty-seven thousand

103,727,495 = One hundred three million seven hundred twenty-seven thousand four hundred and ninety-five

I hope this answer helps you! (I also hope I understood your answer properly and got the answer that you needed :D)

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Haos dog ate 40 cns of dog food in 31 day. how many cans should hao buy to feed his dog in 6 days
Crank
The answer is 8. 40 / 31 = 1.29032258. Multiply that by 6 and you have 7.74193548. Round up because you can't buy 7.7 cans of dog food.
7 0
3 years ago
Can someone please answer there is one problem. There's a picture! Thank you!
miss Akunina [59]
7/2= radius (3.5)
V=πr2^<span>h
V=</span><span>π3.52*12
V= 461.81 </span>
3 0
3 years ago
Read 2 more answers
Is the point (1, -3) a solution to the system? Show all work
Studentka2010 [4]

Answer:

The point P(1,-3) is not a solution to the system.

Step-by-step explanation:

Given  \left \{ {{y-x+2}} \right.  

Let a point be P(1,-3)

Here x = 1 ; y = -3

Substituting the values of x,y in the function

\left \{ {{y-x+2}} \right.

For y<x-1

-3 < 1-1

-3<0 (True)

now for,

y>-x+2

-3 > -1 + 2

-3 > 1 (False)

Hence the point is not a solution to the system.

6 0
3 years ago
Restless Leg Syndrome and Fibromyalgia
mixas84 [53]

Answer:

The probability that a person with restless leg syndrome has fibromyalgia is 0.1833.

Step-by-step explanation:

Denote the events as follows:

<em>F</em> = a person with fibromyalgia

<em>R</em> = a person having restless leg syndrome

The information provided is as follows:

P (R | F) = 0.33

P (R | F') = 0.03

P (F) = 0.02

Consider the tree diagram attached below.

Compute the probability that a person with restless leg syndrome has fibromyalgia as follows:

P(F|R)=\frac{P(R|F)P(F)}{P(R|F)P(F)+P(R|F')P(F')}\\\\=\frac{(0.33\times 0.02)}{(0.33\times 0.02)+(0.03\times 0.98)}\\\\=0.183333\\\\\approx 0.1833

Thus, the probability that a person with restless leg syndrome has fibromyalgia is 0.1833.

6 0
3 years ago
Which expression is equivalent to (3^2)^-2?<br> A.)–81<br> B.)–12<br> C.)1/18<br> D.)1/12
kobusy [5.1K]
(3^2)^-2
9
9^-2 = 1/9^2 ---> 1/81
should be 1/81
7 0
4 years ago
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