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erik [133]
3 years ago
12

What table of values goes with the equation y = |-2 x |?

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
4 0
Graph the absolute value using the vertex and a few selected points.

x: -2, -1, 0, 1, 2
y: 4, 2, 0, 2, 4

Hope this helps! :)
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Jamie evaluated this expression. StartFraction left-bracket (2 cubed) (2) right-bracket Superscript 4 Baseline Over 2 Superscrip
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Answer:

<h3>1/8</h3>

Step-by-step explanation:

Given the expression

\frac{(2^3)(2)^4}{2^{10}} \\

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\frac{a^m}{a^n}  = a^{m-n}\\a^m \times a^n = a^{m+n}

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Step 1: Multiplication rule

=\frac{(2^3)(2)^4}{2^{10}} \\= \frac{2^{3+4}}{2^{10}}\\= \frac{2^7}{2^{10}}

Using the division rule of exponent (Quotient of powers);

= \frac{2^7}{2^{10}} \\= 2^{7-10}\\= 2^{-3}\\also \ a^{-m} = \frac{1}{a^m}\\ 2^{-3}=  \frac{1}{2^3}\\\frac{1}{2^3} = \frac{1}{8}

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If you buy five of the XYZ bonds with $8 commission for each how much will it cost?
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3 years ago
The function f has first derivative given by f'(x)=(x)^1/2/1+x+x^3. What is the x-coordinate of the inflection point of the grap
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Inflection at f'(x) = 0 
<span>
x^1/2 / (1 + x + x^3) = 0 </span>

<span>The x coordinate is x = 0 </span>
<span>
or "C" from your choices there. </span>

<span>The simplest way is to notice that this happens when x = 0. The reason is you got: </span>
<span>
x^1/2 / (some expression) </span>
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at x = 0 the numerator is 0 so unless the denominator is also 0 the result is 0. </span>
<span>
The denominator for x = 0 is 1 so you get </span>
<span>
0/1 = 0.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
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