All categories

3 years ago

Prove, cotx -tanx= 2 cot2x

Mathematics

1 answer:

ra1l [238]3 years ago

4 0

Step-by-step explanation:

cotx- tanx= 2cot2x

L.H.S

 cosx/sinx- sinx/cosx

(cos²x- sin²x)/ sinxcosx

[ cos²x-(1-cos²x)]/sinxcosx

( 2cos²x-1)/sinxcosx

2cosx/ 2sinxcosx

2cot2x

You might be interested in

If f(x) = square root of x+3, what is the equation for f–1(x)? f–1(x) = x2 - 3 f–1(x) = x2 + 3 f–1(x) = (x - 3) 2 f–1(x) = (x +

cupoosta [38]

Answer:

$\Large \boxed{\sf \ \ f^{-1}(x)=x^2-3 \ \ }$

Step-by-step explanation:

Hello,

$\text{For }x+3\geq 0\\\\f(x)=\sqrt{x+3}\\\\x=(fof^{-1})(x)=f(f^{-1}(x))=\sqrt{f^{-1}(x)+3}\\\\\text{*** take the square ***}\\\\f^{-1}(x)+3=x^2\\\\\text{*** subtract 3 from both sides ***}\\\\\large \boxed{\sf \ \ f^{-1}(x)=x^2-3 \ \ }\\$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

3 0

3 years ago

Positive square root of 15376 by factors

pashok25 [27]

15376
/ I
961 16
/ I / I
31 31 4 4

31 × 4 = 124

The square root of 15376 is 124

6 0

3 years ago

Six more than a number y

Flura [38]

Answer:

wdum

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Three points, A, B, and C exists in space such that B is "between" A and C. It is known that AB=7, BC=4, and AC=9. Are points A,

LenKa [72]

Two or more points are said to be collinear if they lie on the same straight line.

Given a straight line XY, with a point P on the straight line between point X and Y, then
XP + PY = XY

From the question, it was given that AB = 7 and BC = 4, so if A, B, C are colinear, then
AB + BC = AC
i.e. 7 + 4 = 11

But, from the equation, AC = 9.

Therefore, points A, B and C are not collinear.

7 0

3 years ago

Your $128 regular pay, plus tips, was $237. How much were the tips?

Amanda [17]

Just subtract them- $109

7 0

3 years ago

Read 2 more answers