Answer:
DV/dt = 0,2355 m³/min
Step-by-step explanation:
Conical tank volume V = 1/3 *π*r²*h
r radius at the top 2 meters
when depth of water is 3 meters the radius of the level of water is:
let α angle of vertex of cone then
tan∠α = 2/8 tan∠α = 1/4 tan∠α = 0,25
At the same time when water is at 3 meters depth radius is
tan∠α = r/3 0,25*3= r r = 0,75 m
Now
DV/dt = (1/3)*π*r²*Dh/dt
Dh/dt = 0,4 meters/min
By substitution
DV/dt = 0,2355 m³/min
Answer:
-1
Step-by-step explanation:
= 
= 
= -1
Answer:
B
Step-by-step explanation:
Supplementary angles sum to 180°, hence
3x + 9 + 2x + 2 = 180, that is
5x + 11 = 180 ( subtract 11 from both sides )
5x = 169 ( divide both sides by 5 )
x = 33.8
Hence the smaller angle has a measure of
2x + 2 = (2 × 33.8) + 2 = 67.6 + 2 = 69.6° → B
Answer:
may we please have some more info on the question?
Step-by-step explanation:
Answer:
7*(2a-1)
Step-by-step explanation:
