Answer:
D
Step-by-step explanation:
First, let us figure out what is graphed and then manipulate each answer to try to match it.
The one with a positive slope is
The one with the negative slope is
Now that we have our graphed system of inequalities, we can try to match them to an answer.
A. while the x-2 is the same, the other does not have an x, so it cannot match.
B. The second inequality has the wrong sign, so it is impossible for this to be our answer.
C. When each of these are solved for y, you get 
. Neither of these match so this cannot be correct.
D. When the first inequality is solved you get
When the second inequality is solved you get
As both of these answers match our graphed inequalities, D is the correct answer.
Answer:
The scale factor is not 2
Step-by-step explanation:
Given
See attachment for the dilated triangles
Triangle ABC is dilated through center point O to form triangle A'B'C'.
From the attachment, we have:
i.e. the distance from the center point to C
and
i.e. the distance from the center point to C'
The length of OC' is calculated using:
The scale factor (k) is then calculated by dividing OC' by OC
Hence, Tiffany's claim is incorrect.
6 + 8x = 30
Problem written out
8x = 24
Subtracted 6 to get 8x alone
x = 3
Divided 8 to get your answer!
Answer:
1. all real numbers less than or equal to 4 = </= 4.
Answer = YES!
2. all real numbers less than or equal to -3 = </= -3.
Answer = YES!
3. all real numbers greater than or equal to 4 = >/= 4
Answer = YES!
4. all real numbers greater than or equal to -3 = >/= -3
Answer = NO!
Step-by-step explanation:
1. all real numbers less than or equal to 4 = </= 4.
1 + 1 = 2
1 + 2 = 3
2 + 2 = 4
2. all real numbers less than or equal to -3 = </= -3.
1 - 1 = 0
1 - 2 = -1
1 - 3 = -2
1 - 4 = -3
3. all real numbers greater than or equal to 4
1 + 1 = 2
1 + 2 = 3
1 + 3 = 4
1 + 4 = 5
4. all real numbers greater than or equal to -3
1 - 1 = 0
1 - 2 = -1
1 - 3 = -2
1 - 4 = -3
Since we are already given the amount of jumps from the first trial, and how much it should be increased by on each succeeding trial, we can already solve for the amount of jumps from the first through tenth trials. Starting from 5 and adding 3 each time, we get: 5 8 (11) 14 17 20 23 26 29 32, with 11 being the third trial.
Having been provided 2 different sigma notations, which I assume are choices to the question, we can substitute the initial value to see if it does match the result of the 3rd trial which we obtained by manual adding.
Let us try it below:
Sigma notation 1:
10
<span> Σ (2i + 3)
</span>i = 3
@ i = 3
2(3) + 3
12
The first sigma notation does not have the same result, so we move on to the next.
10
<span> Σ (3i + 2)
</span><span>i = 3
</span>
When i = 3; <span>3(3) + 2 = 11. (OK)
</span>
Since the 3rd trial is a match, we test it with the other values for the 4th through 10th trials.
When i = 4; <span>3(4) + 2 = 14. (OK)
</span>When i = 5; <span>3(5) + 2 = 17. (OK)
</span>When i = 6; <span>3(6) + 2 = 20. (OK)
</span>When i = 7; 3(7) + 2 = 23. (OK)
When i = 8; <span>3(8) + 2 = 26. (OK)
</span>When i = 9; <span>3(9) + 2 = 29. (OK)
</span>When i = 10; <span>3(10) + 2 = 32. (OK)
Adding the results from her 3rd through 10th trials: </span><span>11 + 14 + 17 + 20 + 23 + 26 + 29 + 32 = 172.
</span>
Therefore, the total jumps she had made from her third to tenth trips is 172.
